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Ravi, Hari and Sanjay are three typists, who working simultaneously, can type 228 pages in four hours. In one hour, Sanjay can type as many pages more than Hari as Hari can type more than Ravi. During a period of five hours, Sanjay can type as many passages as Ravi can, during seven hours.
Quantity I: Number of pages typed by Ravi
Quantity II: Number of pages typed by Hari
  • a)
    Quantity I > Quantity II
  • b)
    Quantity I < Quantity II
  • c)
    Quantity I ≥ Quantity II
  • d)
    Quantity I ≤ Quantity II
  • e)
    Quantity I = Quantity II or relation cannot be established
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Ravi, Hari and Sanjay are three typists, who working simultaneously, c...
Let Ravi, Hari and Sanjay can type x, y, and z pages respectively in 1 h. Therefore, they together can type 4(x + y + z) pages in 4 h
∴ 4(x + y + z) = 228
⇒ x + y + z = 57 …..(i)
Also, z – y = y – x
i.e., 2y = x + z ……(ii)
5z = 7x ……(iii)
From Eqs. (i) and (ii), we get
3y = 57
⇒ y = 19
From Eq. (ii), x + z = 38
x = 16 and z = 22
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Most Upvoted Answer
Ravi, Hari and Sanjay are three typists, who working simultaneously, c...
Let's assume that Ravi can type x pages per hour.

Since Hari can type more pages than Ravi, Hari can type (x + y) pages per hour, where y is a positive number.

And since Sanjay can type more pages than Hari, Sanjay can type (x + y + z) pages per hour, where z is a positive number.

According to the given information, Ravi, Hari, and Sanjay working simultaneously can type 228 pages in four hours. So, in one hour, they can type 228/4 = 57 pages.

We can set up the following equation based on the information given:

x + (x + y) + (x + y + z) = 57

Simplifying the equation, we get:

3x + 2y + z = 57 ------(1)

During a period of five hours, Sanjay can type as many pages as Ravi can. So, in five hours, they can type 5(x + y + z) pages.

During a period of seven hours, Sanjay can type as many pages as Ravi can. So, in seven hours, they can type 7(x + y) pages.

We can set up the following equation based on the above information:

5(x + y + z) = 7(x + y)

Simplifying the equation, we get:

5x + 5y + 5z = 7x + 7y

2x + 2y + 5z = 0 ------(2)

Now, we have two equations:

3x + 2y + z = 57 ------(1)
2x + 2y + 5z = 0 ------(2)

To solve these equations, we can eliminate y by subtracting equation (1) from equation (2):

(2x + 2y + 5z) - (3x + 2y + z) = 0 - 57

-x + 4z = -57

x - 4z = 57 ------(3)

Now, we have two equations:

x - 4z = 57 ------(3)
2x + 2y + 5z = 0 ------(2)

We can solve these equations to find the values of x and z.

Multiplying equation (3) by 2, we get:

2x - 8z = 114 ------(4)

Subtracting equation (4) from equation (2), we get:

(2x + 2y + 5z) - (2x - 8z) = 0 - 114

10z = -114

z = -11.4

Since z is a positive number, the assumption that Sanjay can type more pages than Hari is incorrect.

Therefore, we cannot determine the values of pages typed by Ravi and Hari using the given information.

Hence, the answer is (E) Quantity I cannot be determined from the information given.
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Ravi, Hari and Sanjay are three typists, who working simultaneously, can type 228 pages in four hours. In one hour, Sanjay can type as many pages more than Hari as Hari can type more than Ravi. During a period of five hours, Sanjay can type as many passages as Ravi can, during seven hours.Quantity I: Number of pages typed by RaviQuantity II: Number of pages typed by Haria)Quantity I > Quantity IIb)Quantity I < Quantity IIc)Quantity I ≥ Quantity IId)Quantity I ≤ Quantity IIe)Quantity I = Quantity II or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer?
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Ravi, Hari and Sanjay are three typists, who working simultaneously, can type 228 pages in four hours. In one hour, Sanjay can type as many pages more than Hari as Hari can type more than Ravi. During a period of five hours, Sanjay can type as many passages as Ravi can, during seven hours.Quantity I: Number of pages typed by RaviQuantity II: Number of pages typed by Haria)Quantity I > Quantity IIb)Quantity I < Quantity IIc)Quantity I ≥ Quantity IId)Quantity I ≤ Quantity IIe)Quantity I = Quantity II or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Ravi, Hari and Sanjay are three typists, who working simultaneously, can type 228 pages in four hours. In one hour, Sanjay can type as many pages more than Hari as Hari can type more than Ravi. During a period of five hours, Sanjay can type as many passages as Ravi can, during seven hours.Quantity I: Number of pages typed by RaviQuantity II: Number of pages typed by Haria)Quantity I > Quantity IIb)Quantity I < Quantity IIc)Quantity I ≥ Quantity IId)Quantity I ≤ Quantity IIe)Quantity I = Quantity II or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ravi, Hari and Sanjay are three typists, who working simultaneously, can type 228 pages in four hours. In one hour, Sanjay can type as many pages more than Hari as Hari can type more than Ravi. During a period of five hours, Sanjay can type as many passages as Ravi can, during seven hours.Quantity I: Number of pages typed by RaviQuantity II: Number of pages typed by Haria)Quantity I > Quantity IIb)Quantity I < Quantity IIc)Quantity I ≥ Quantity IId)Quantity I ≤ Quantity IIe)Quantity I = Quantity II or relation cannot be establishedCorrect answer is option 'B'. Can you explain this answer?.
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