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Assume that the H2 molecule behaves like a harmonic oscillator with a force constant k = 573 N/m the vibrational quantum number, corresponding to its dissociation energy 4.5 eV, is

  • a)
    n = 6

  • b)
    n = 7

  • c)
    n = 8

  • d)
    n = 15

Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Assume that the H2 molecule behaves like a harmonic oscillator with a ...
For H2, the reduced mass (μ) 

Therefore, frequency of oscillation of the molecule is given by



For vibrational quantum number (n) corresponding to dissociation energy (Ediss), we have





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Most Upvoted Answer
Assume that the H2 molecule behaves like a harmonic oscillator with a ...
Given information:
- Force constant k = 573 N/m
- Dissociation energy = 4.5 eV

We can use the formula for the vibrational energy levels of a harmonic oscillator:

E = (n + 1/2)hν

where:
- E is the vibrational energy level
- n is the vibrational quantum number
- h is Planck's constant
- ν is the vibrational frequency

To find the vibrational frequency, we can use the formula:

ν = 1/2π * √(k/m)

where m is the reduced mass of the H2 molecule, which is half the mass of a single H atom:

m = 1/2 * m(H) = 1/2 * 1.00794 u = 0.50397 u

where u is the atomic mass unit.

Thus, the vibrational frequency is:

ν = 1/2π * √(573 N/m / (0.50397 u * 1.66054 x 10^-27 kg/u)) = 1.041 x 10^14 Hz

To find the vibrational quantum number corresponding to a dissociation energy of 4.5 eV, we can use the formula:

E(n) - E(n-1) = hν

where E(n) and E(n-1) are the energies of two adjacent vibrational levels.

Solving for n, we get:

n = (E(dissociation) / hν) + 1/2

where E(dissociation) is the dissociation energy in joules.

Converting 4.5 eV to joules:

E(dissociation) = 4.5 eV * 1.60218 x 10^-19 J/eV = 7.21581 x 10^-19 J

Substituting the values:

n = (7.21581 x 10^-19 J / (6.62607 x 10^-34 J s * 1.041 x 10^14 Hz)) + 1/2 = 8.06

Rounding to the nearest integer, we get n = 8, which is the correct answer (option C).
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Assume that the H2 molecule behaves like a harmonic oscillator with a force constant k = 573 N/m the vibrational quantum number, corresponding to its dissociation energy 4.5 eV,isa)n = 6b)n = 7c)n = 8d)n = 15Correct answer is option 'C'. Can you explain this answer?
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