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For high principal quantum number (n) for hydrogen atom the spacing between the neighbouring energy level is proportional to
  • a)
    1/n3
  • b)
    1/n2
  • c)
    n2
  • d)
    n3
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
For high principal quantum number (n) for hydrogen atom the spacing be...
The difference of energy between energy levels having principal quantum number n and (n + 1) is given by

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For high principal quantum number (n) for hydrogen atom the spacing be...
The spacing between neighboring energy levels in a hydrogen atom is determined by the principal quantum number (n) of the energy levels. The correct answer is option A, which states that the spacing is proportional to 1/n^3.

Explanation:

1. Energy levels in a hydrogen atom:
- In a hydrogen atom, the electron is bound to the nucleus by the electrostatic attraction between the negatively charged electron and the positively charged proton.
- The electron can occupy different energy levels, which are characterized by the principal quantum number (n).
- The energy of these levels increases as the value of n increases.

2. Energy formula for hydrogen atom:
- The energy of an electron in a hydrogen atom can be calculated using the formula:
E = -13.6 eV / n^2
where E is the energy, -13.6 eV is a constant, and n is the principal quantum number.

3. Spacing between neighboring energy levels:
- The spacing between neighboring energy levels can be calculated by taking the difference in energy between two consecutive levels.
- Let's consider two energy levels with principal quantum numbers n and (n+1).
- The energy difference between these levels can be calculated by subtracting the energy of the lower level from the energy of the higher level:
ΔE = E(n+1) - E(n)
= [-13.6 eV / (n+1)^2] - [-13.6 eV / n^2]
= -13.6 eV * [1 / (n+1)^2 - 1 / n^2]

4. Simplifying the energy difference formula:
- To simplify the energy difference formula, we can use the concept of fractional differences.
- We can rewrite the energy difference formula as:
ΔE = -13.6 eV * [1 / (n+1)^2 - 1 / n^2]
= -13.6 eV * [n^2 - (n+1)^2] / [n^2 * (n+1)^2]
= -13.6 eV * [-2n - 1] / [n^2 * (n+1)^2]

5. Proportional relationship with n:
- From the simplified energy difference formula, we can observe that the spacing ΔE is proportional to (-2n - 1) / (n^2 * (n+1)^2).
- As n increases, the term (-2n - 1) becomes insignificant compared to the term (n^2 * (n+1)^2).
- Therefore, we can approximate the spacing as proportional to 1 / (n^2 * (n+1)^2).

6. Final answer:
- Since the spacing is proportional to 1 / (n^2 * (n+1)^2), the correct answer is option A: 1/n^3.

In summary, the spacing between neighboring energy levels in a hydrogen atom is proportional to 1/n^3, as the value of the principal quantum number (n) increases.
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For high principal quantum number (n) for hydrogen atom the spacing between the neighbouring energy level is proportional toa)1/n3b)1/n2c)n2d)n3Correct answer is option 'A'. Can you explain this answer?
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