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Consider a crystal with base-centered-cubic lattice with positions of basis atoms at (0, 0, 0) and 
The lattice plane for which there is no diffraction peak is
  • a)
    (1 1 1)
  • b)
    (1 2 0) 
  • c)
    (1 1 0) 
  • d)
    (2 2 2)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Consider a crystal with base-centered-cubic lattice with positions of ...
Structure factor 
‘S' is non-zero only if (v1 + v2) is even and there is no condition for v3
If (v1 + v2) is odd. there will be no diffraction peak.
For plane (1 2 0). v1 + v2 = 3 (odd)
Hence, for plane (1 2 0). there is no diffraction peak.
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