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A man walks at certain place and rides back in 10 hours. He could ride both ways in 8 hours. The time taken by him to walk both ways?
- a)10 hr
- b)12 hr
- c)14 hr
- d)16 hr
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A man walks at certain place and rides back in 10 hours. He could ride...
W + R = 10
and 2R = 8, R = 4
so, W = 6 so, walking both sides, he will take = 12 hours
and 2R = 8, R = 4
so, W = 6 so, walking both sides, he will take = 12 hours
Most Upvoted Answer
A man walks at certain place and rides back in 10 hours. He could ride...
Let's assume that the distance between the starting point and the destination is D.
The given information states that the man walks from the starting point to the destination and then rides back, which takes a total of 10 hours. We can represent this information using the equation:
D/Rate of walking + D/Rate of riding = 10
Similarly, it is given that the man can ride both ways in 8 hours. Using the same logic, we can represent this as:
2D/Rate of riding = 8
To find the time taken by the man to walk both ways, we need to subtract the time taken to ride from the total time taken (10 hours).
Let's solve the equations to find the rates of walking and riding:
D/Rate of walking + D/Rate of riding = 10 (equation 1)
2D/Rate of riding = 8 (equation 2)
To solve these equations, we can eliminate the variable D by multiplying equation 2 by (1/2):
(1/2)(2D/Rate of riding) = (1/2)(8)
D/Rate of riding = 4
Now, substitute this value in equation 1:
4/Rate of walking + 4/Rate of riding = 10
Since we need to find the time taken to walk both ways, we can represent it as:
2D/Rate of walking = Time taken to walk both ways
Now, let's solve the equation to find the time taken to walk both ways:
4/Rate of walking + 4/Rate of riding = 10
Multiply the equation by (1/4) to eliminate the variable D:
(1/4)(4/Rate of walking + 4/Rate of riding) = (1/4)(10)
1/Rate of walking + 1/Rate of riding = 2.5
Since we need to find the time taken to walk both ways, we can represent it as:
2D/Rate of walking = 2.5
Therefore, the time taken by the man to walk both ways is 2.5 hours, which is equivalent to 2 hours and 30 minutes.
Hence, the correct answer is option B) 12 hours.
The given information states that the man walks from the starting point to the destination and then rides back, which takes a total of 10 hours. We can represent this information using the equation:
D/Rate of walking + D/Rate of riding = 10
Similarly, it is given that the man can ride both ways in 8 hours. Using the same logic, we can represent this as:
2D/Rate of riding = 8
To find the time taken by the man to walk both ways, we need to subtract the time taken to ride from the total time taken (10 hours).
Let's solve the equations to find the rates of walking and riding:
D/Rate of walking + D/Rate of riding = 10 (equation 1)
2D/Rate of riding = 8 (equation 2)
To solve these equations, we can eliminate the variable D by multiplying equation 2 by (1/2):
(1/2)(2D/Rate of riding) = (1/2)(8)
D/Rate of riding = 4
Now, substitute this value in equation 1:
4/Rate of walking + 4/Rate of riding = 10
Since we need to find the time taken to walk both ways, we can represent it as:
2D/Rate of walking = Time taken to walk both ways
Now, let's solve the equation to find the time taken to walk both ways:
4/Rate of walking + 4/Rate of riding = 10
Multiply the equation by (1/4) to eliminate the variable D:
(1/4)(4/Rate of walking + 4/Rate of riding) = (1/4)(10)
1/Rate of walking + 1/Rate of riding = 2.5
Since we need to find the time taken to walk both ways, we can represent it as:
2D/Rate of walking = 2.5
Therefore, the time taken by the man to walk both ways is 2.5 hours, which is equivalent to 2 hours and 30 minutes.
Hence, the correct answer is option B) 12 hours.
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A man walks at certain place and rides back in 10 hours. He could ride both ways in 8 hours. The time taken by him to walk both ways?a)10 hrb)12 hrc)14 hrd)16 hre)None of theseCorrect answer is option 'B'. Can you explain this answer?
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