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Using semi-empirical mass formula, the most stable isobar with mass number A = 65. corresponds to
- a)Z = 27
- b)Z = 28
- c)Z = 29
- d)Z = 30
Correct answer is option 'C'. Can you explain this answer?
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Using Semi-Empirical Mass Formula to Determine the Most Stable Isobar with Mass Number A = 65
The Semi-Empirical Mass Formula is used to determine the binding energy of a nucleus based on its mass number and atomic number. This formula takes into account five different terms that contribute to the binding energy of a nucleus. These terms are:
1. Volume term (A)
2. Surface term (A^(2/3))
3. Coulomb term (Z^2/A^(1/3))
4. Asymmetry term [(A-2Z)^2/A]
5. Pairing term (±a/A^(1/2))
To determine the most stable isobar with mass number A = 65, we can use the Semi-Empirical Mass Formula and vary the atomic number (Z) to find the maximum binding energy.
Here are the steps to follow:
1. Calculate the binding energy of the nucleus using the Semi-Empirical Mass Formula with A = 65 and different values of Z.
2. Plot the binding energy as a function of Z.
3. Identify the value of Z that corresponds to the maximum binding energy.
Using these steps, we can determine that the most stable isobar with mass number A = 65 corresponds to Z = 29.
Therefore, the correct answer is option 'C'.
The Semi-Empirical Mass Formula is used to determine the binding energy of a nucleus based on its mass number and atomic number. This formula takes into account five different terms that contribute to the binding energy of a nucleus. These terms are:
1. Volume term (A)
2. Surface term (A^(2/3))
3. Coulomb term (Z^2/A^(1/3))
4. Asymmetry term [(A-2Z)^2/A]
5. Pairing term (±a/A^(1/2))
To determine the most stable isobar with mass number A = 65, we can use the Semi-Empirical Mass Formula and vary the atomic number (Z) to find the maximum binding energy.
Here are the steps to follow:
1. Calculate the binding energy of the nucleus using the Semi-Empirical Mass Formula with A = 65 and different values of Z.
2. Plot the binding energy as a function of Z.
3. Identify the value of Z that corresponds to the maximum binding energy.
Using these steps, we can determine that the most stable isobar with mass number A = 65 corresponds to Z = 29.
Therefore, the correct answer is option 'C'.
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Usingsemi-empirical mass formula, the most stable isobar with mass number A = 65. corresponds toa)Z = 27b)Z = 28c)Z = 29d)Z = 30Correct answer is option 'C'. Can you explain this answer?
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Usingsemi-empirical mass formula, the most stable isobar with mass number A = 65. corresponds toa)Z = 27b)Z = 28c)Z = 29d)Z = 30Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Usingsemi-empirical mass formula, the most stable isobar with mass number A = 65. corresponds toa)Z = 27b)Z = 28c)Z = 29d)Z = 30Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Usingsemi-empirical mass formula, the most stable isobar with mass number A = 65. corresponds toa)Z = 27b)Z = 28c)Z = 29d)Z = 30Correct answer is option 'C'. Can you explain this answer?.
Usingsemi-empirical mass formula, the most stable isobar with mass number A = 65. corresponds toa)Z = 27b)Z = 28c)Z = 29d)Z = 30Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Usingsemi-empirical mass formula, the most stable isobar with mass number A = 65. corresponds toa)Z = 27b)Z = 28c)Z = 29d)Z = 30Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Usingsemi-empirical mass formula, the most stable isobar with mass number A = 65. corresponds toa)Z = 27b)Z = 28c)Z = 29d)Z = 30Correct answer is option 'C'. Can you explain this answer?.
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