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Mass of α - particle = 4.002603 amu,mass of proton = 1.007825 amu,mass of neutron = 1.008664 amu. Taking 1 amu = 931 MeV,the binding energy of a-panicle is________(upto two decimal places).Correct answer is '28.28'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared
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Mass of α - particle = 4.002603 amu,mass of proton = 1.007825 amu,mass of neutron = 1.008664 amu. Taking 1 amu = 931 MeV,the binding energy of a-panicle is________(upto two decimal places).Correct answer is '28.28'. Can you explain this answer?, a detailed solution for Mass of α - particle = 4.002603 amu,mass of proton = 1.007825 amu,mass of neutron = 1.008664 amu. Taking 1 amu = 931 MeV,the binding energy of a-panicle is________(upto two decimal places).Correct answer is '28.28'. Can you explain this answer? has been provided alongside types of Mass of α - particle = 4.002603 amu,mass of proton = 1.007825 amu,mass of neutron = 1.008664 amu. Taking 1 amu = 931 MeV,the binding energy of a-panicle is________(upto two decimal places).Correct answer is '28.28'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Mass of α - particle = 4.002603 amu,mass of proton = 1.007825 amu,mass of neutron = 1.008664 amu. Taking 1 amu = 931 MeV,the binding energy of a-panicle is________(upto two decimal places).Correct answer is '28.28'. Can you explain this answer? tests, examples and also practice GATE tests.