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Two nucleons are at a separation of 1 fm. The net force between them is F1 if both are neutrons, F2 if both are protons, and F3 if one is a proton and the other is a neutron.
- a)F1 > F 2 > F3
- b)F2 > F1 > F3
- c)F1 = F3 > F2
- d)F1 = F2 > F3
Correct answer is option 'C'. Can you explain this answer?
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Two nucleons are at a separation of 1 fm. The net force between them i...
Nuclear forces will be same all three cases but total force F2 will be smaller because of electrostatic repulsion between two protons.
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Two nucleons are at a separation of 1 fm. The net force between them i...
To calculate the force between two nucleons, we can use Coulomb's law, which states that the force between two charged particles is proportional to the product of their charges and inversely proportional to the square of the distance between them.
For two neutrons, the net force between them would be F1. Neutrons have no charge, so the force between them would be zero. Therefore, F1 = 0.
For two protons, the net force between them would be F2. Protons have a charge of +1e, where e is the elementary charge. The force between them is given by:
F2 = k * (q1 * q2) / r^2
where k is the Coulomb's constant (approximately equal to 8.99 x 10^9 N m^2/C^2), q1 and q2 are the charges of the protons (+1e), and r is the separation between them (1 fm = 1 x 10^-15 m).
F2 = (8.99 x 10^9 N m^2/C^2) * (+1e * +1e) / (1 x 10^-15 m)^2
Now we can calculate F2. Let's substitute the values:
F2 = (8.99 x 10^9 N m^2/C^2) * (1.6 x 10^-19 C)^2 / (1 x 10^-15 m)^2
F2 ≈ 2.305 N
Therefore, F2 is approximately 2.305 N.
For one proton and one neutron, the net force between them would be F3. Since the neutron is neutral, only the proton contributes to the force. Using the same formula as before, we have:
F3 = k * (q1 * q2) / r^2
F3 = (8.99 x 10^9 N m^2/C^2) * (+1e * 0) / (1 x 10^-15 m)^2
F3 = 0
Therefore, F3 is zero.
To summarize:
a) F1 = 0
b) F2 ≈ 2.305 N
c) F3 = 0
For two neutrons, the net force between them would be F1. Neutrons have no charge, so the force between them would be zero. Therefore, F1 = 0.
For two protons, the net force between them would be F2. Protons have a charge of +1e, where e is the elementary charge. The force between them is given by:
F2 = k * (q1 * q2) / r^2
where k is the Coulomb's constant (approximately equal to 8.99 x 10^9 N m^2/C^2), q1 and q2 are the charges of the protons (+1e), and r is the separation between them (1 fm = 1 x 10^-15 m).
F2 = (8.99 x 10^9 N m^2/C^2) * (+1e * +1e) / (1 x 10^-15 m)^2
Now we can calculate F2. Let's substitute the values:
F2 = (8.99 x 10^9 N m^2/C^2) * (1.6 x 10^-19 C)^2 / (1 x 10^-15 m)^2
F2 ≈ 2.305 N
Therefore, F2 is approximately 2.305 N.
For one proton and one neutron, the net force between them would be F3. Since the neutron is neutral, only the proton contributes to the force. Using the same formula as before, we have:
F3 = k * (q1 * q2) / r^2
F3 = (8.99 x 10^9 N m^2/C^2) * (+1e * 0) / (1 x 10^-15 m)^2
F3 = 0
Therefore, F3 is zero.
To summarize:
a) F1 = 0
b) F2 ≈ 2.305 N
c) F3 = 0
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Two nucleons are at a separation of 1 fm. The net force between them is F1 if both are neutrons, F2 if both are protons, and F3 if one is a proton and the other is a neutron. a)F1 > F 2 > F3b)F2 > F1 > F3c)F1 = F3 > F2d)F1 = F2 > F3Correct answer is option 'C'. Can you explain this answer?
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