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An amide (A) C3H7NO on hydrolysis gives an amine (B) and an acid (C). B gives carbylamines reaction where as C reduces Tollen’s reagent. (A) is
- a)CH3CONHCH3
- b)CH3CH2CONO2
- c)HCONHC2H5
- d)HCON (CH3)2
Correct answer is option 'C'. Can you explain this answer?
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An amide (A) C3H7NO on hydrolysis gives an amine (B) and an acid (C). ...
's reagent to give a silver mirror. Identify the amide A, amine B, and acid C.
To begin, let's analyze the given information:
1. Amide A (C3H7NO) on hydrolysis gives an amine B and an acid C.
2. Amine B undergoes the carbylamines reaction.
3. Acid C reduces Tollen's reagent to give a silver mirror.
Now, let's break it down step by step:
1. Hydrolysis of amide A (C3H7NO) will break the amide bond and result in the formation of an amine and an acid. The amine will be compound B, and the acid will be compound C.
C3H7NO + H2O → C3H7NH2 (B) + HOOC (C)
2. Amine B (C3H7NH2) undergoes the carbylamines reaction. The carbylamines reaction occurs when a primary amine reacts with chloroform (CHCl3) in the presence of a strong base such as potassium hydroxide (KOH). This reaction forms an isocyanide (carbylamine) compound.
C3H7NH2 + CHCl3 + KOH → C3H7NC (carbylamines reaction)
3. Acid C (HOOC) reduces Tollen's reagent to give a silver mirror. Tollen's reagent, also known as ammoniacal silver nitrate, is a solution of silver nitrate (AgNO3) in aqueous ammonia (NH3). When acid C reacts with Tollen's reagent, it produces a reducing agent that reduces the silver ions in the reagent to metallic silver, forming a silver mirror.
HOOC + 2AgNO3 + 2NH3 → Ag2 + 2NH4NO3 + H2O + silver mirror
Based on the reactions and given information, we can determine the identities of the compounds:
Amide A: C3H7NO
Amine B: C3H7NH2
Acid C: HOOC
To begin, let's analyze the given information:
1. Amide A (C3H7NO) on hydrolysis gives an amine B and an acid C.
2. Amine B undergoes the carbylamines reaction.
3. Acid C reduces Tollen's reagent to give a silver mirror.
Now, let's break it down step by step:
1. Hydrolysis of amide A (C3H7NO) will break the amide bond and result in the formation of an amine and an acid. The amine will be compound B, and the acid will be compound C.
C3H7NO + H2O → C3H7NH2 (B) + HOOC (C)
2. Amine B (C3H7NH2) undergoes the carbylamines reaction. The carbylamines reaction occurs when a primary amine reacts with chloroform (CHCl3) in the presence of a strong base such as potassium hydroxide (KOH). This reaction forms an isocyanide (carbylamine) compound.
C3H7NH2 + CHCl3 + KOH → C3H7NC (carbylamines reaction)
3. Acid C (HOOC) reduces Tollen's reagent to give a silver mirror. Tollen's reagent, also known as ammoniacal silver nitrate, is a solution of silver nitrate (AgNO3) in aqueous ammonia (NH3). When acid C reacts with Tollen's reagent, it produces a reducing agent that reduces the silver ions in the reagent to metallic silver, forming a silver mirror.
HOOC + 2AgNO3 + 2NH3 → Ag2 + 2NH4NO3 + H2O + silver mirror
Based on the reactions and given information, we can determine the identities of the compounds:
Amide A: C3H7NO
Amine B: C3H7NH2
Acid C: HOOC
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An amide (A) C3H7NO on hydrolysis gives an amine (B) and an acid (C). B gives carbylamines reaction where as C reduces Tollen’s reagent. (A) isa)CH3CONHCH3b)CH3CH2CONO2c)HCONHC2H5d)HCON (CH3)2Correct answer is option 'C'. Can you explain this answer?
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An amide (A) C3H7NO on hydrolysis gives an amine (B) and an acid (C). B gives carbylamines reaction where as C reduces Tollen’s reagent. (A) isa)CH3CONHCH3b)CH3CH2CONO2c)HCONHC2H5d)HCON (CH3)2Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An amide (A) C3H7NO on hydrolysis gives an amine (B) and an acid (C). B gives carbylamines reaction where as C reduces Tollen’s reagent. (A) isa)CH3CONHCH3b)CH3CH2CONO2c)HCONHC2H5d)HCON (CH3)2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An amide (A) C3H7NO on hydrolysis gives an amine (B) and an acid (C). B gives carbylamines reaction where as C reduces Tollen’s reagent. (A) isa)CH3CONHCH3b)CH3CH2CONO2c)HCONHC2H5d)HCON (CH3)2Correct answer is option 'C'. Can you explain this answer?.
An amide (A) C3H7NO on hydrolysis gives an amine (B) and an acid (C). B gives carbylamines reaction where as C reduces Tollen’s reagent. (A) isa)CH3CONHCH3b)CH3CH2CONO2c)HCONHC2H5d)HCON (CH3)2Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An amide (A) C3H7NO on hydrolysis gives an amine (B) and an acid (C). B gives carbylamines reaction where as C reduces Tollen’s reagent. (A) isa)CH3CONHCH3b)CH3CH2CONO2c)HCONHC2H5d)HCON (CH3)2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An amide (A) C3H7NO on hydrolysis gives an amine (B) and an acid (C). B gives carbylamines reaction where as C reduces Tollen’s reagent. (A) isa)CH3CONHCH3b)CH3CH2CONO2c)HCONHC2H5d)HCON (CH3)2Correct answer is option 'C'. Can you explain this answer?.
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