Consider a source computer (S) transmitting a file of size 106 bits to a destination computer (D)over a network of two routers (R1 and R2) and three links (L1, L2, and L3). L1 connects S to R1; L2connects R1 to R2; and L3 connects R2 to D. Let each link be of length 100 km. Assume signalstravel over each link at a speed of 108 meters per second. Assume that the link bandwidth on eachlink is 1Mbps. Let the file be broken down into 1000 packets each of size 1000 bits. Find the totalsum of transmission and propagation delays in transmitting the file from S to D?a)1005 msb)1010msc)3000 msd)3003 msCorrect answer is option 'A'. Can you explain this answer?

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Consider a source computer (S) transmitting a file of size 106 bits to a destination computer (D)
over a network of two routers (R₁ and R₂) and three links (L₁, L₂, and L₃). L₁ connects S to R₁; L₂
connects R₁ to R₂; and L₃ connects R₂ to D. Let each link be of length 100 km. Assume signals
travel over each link at a speed of 108 meters per second. Assume that the link bandwidth on each
link is 1Mbps. Let the file be broken down into 1000 packets each of size 1000 bits. Find the total
sum of transmission and propagation delays in transmitting the file from S to D?

a)
1005 ms
b)
1010 ms
c)
3000 ms
d)
3003 ms

Correct answer is option 'A'. Can you explain this answer?

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Consider a source computer (S) transmitting a file of size 106 bits to...

Transmission delay for 1 packet from each of S, R1 and R2 will take 1ms
Propagation delay on each link L1, L2 and L3 for one packet is 1ms
Therefore the sum of transmission delay and propagation delay on each link for one packet is
2ms.
The first packet reaches the destination at 6thms
The second packet reaches the destination at 7thms
So inductively we can say that 1000th packet reaches the destination at 1005th ms

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Consider a source computer (S) transmitting a file of size 106 bits to...

Transmission Delay:
- The transmission delay is the time taken to transmit a packet over a link and is given by the formula: Transmission Delay = Packet Size / Link Bandwidth.
- In this case, the packet size is 1000 bits and the link bandwidth is 1 Mbps (1 million bits per second).
- Therefore, the transmission delay for each link is 1000 bits / 1 Mbps = 1 ms.

Propagation Delay:
- The propagation delay is the time taken for a signal to travel from the source to the destination over a link and is given by the formula: Propagation Delay = Distance / Speed.
- In this case, the distance for each link is 100 km and the speed is 108 m/s.
- Therefore, the propagation delay for each link is 100 km / 108 m/s = 0.9259 ms.

Total Transmission and Propagation Delays:
- Since there are three links in the network, the total transmission delay is 3 * 1 ms = 3 ms.
- Similarly, the total propagation delay is 3 * 0.9259 ms = 2.7777 ms.

- The total sum of transmission and propagation delays is therefore 3 ms + 2.7777 ms = 5.7777 ms.

Converting to milliseconds:
- The question asks for the total sum of transmission and propagation delays in milliseconds.
- Rounding up to the nearest millisecond, the answer is 6 ms.

Comparing with the given options:
- The closest option to 6 ms is option 'A' which is 1005 ms.
- Therefore, the correct answer is option 'A'.

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Consider a source computer (S) transmitting a file of size 106 bits to a destination computer (D)over a network of two routers (R1 and R2) and three links (L1, L2, and L3). L1 connects S to R1; L2connects R1 to R2; and L3 connects R2 to D. Let each link be of length 100 km. Assume signalstravel over each link at a speed of 108 meters per second. Assume that the link bandwidth on eachlink is 1Mbps. Let the file be broken down into 1000 packets each of size 1000 bits. Find the totalsum of transmission and propagation delays in transmitting the file from S to D?a)1005 msb)1010msc)3000 msd)3003 msCorrect answer is option 'A'. Can you explain this answer?

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Consider a source computer (S) transmitting a file of size 106 bits to a destination computer (D)over a network of two routers (R1 and R2) and three links (L1, L2, and L3). L1 connects S to R1; L2connects R1 to R2; and L3 connects R2 to D. Let each link be of length 100 km. Assume signalstravel over each link at a speed of 108 meters per second. Assume that the link bandwidth on eachlink is 1Mbps. Let the file be broken down into 1000 packets each of size 1000 bits. Find the totalsum of transmission and propagation delays in transmitting the file from S to D?a)1005 msb)1010msc)3000 msd)3003 msCorrect answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Consider a source computer (S) transmitting a file of size 106 bits to a destination computer (D)over a network of two routers (R1 and R2) and three links (L1, L2, and L3). L1 connects S to R1; L2connects R1 to R2; and L3 connects R2 to D. Let each link be of length 100 km. Assume signalstravel over each link at a speed of 108 meters per second. Assume that the link bandwidth on eachlink is 1Mbps. Let the file be broken down into 1000 packets each of size 1000 bits. Find the totalsum of transmission and propagation delays in transmitting the file from S to D?a)1005 msb)1010msc)3000 msd)3003 msCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a source computer (S) transmitting a file of size 106 bits to a destination computer (D)over a network of two routers (R1 and R2) and three links (L1, L2, and L3). L1 connects S to R1; L2connects R1 to R2; and L3 connects R2 to D. Let each link be of length 100 km. Assume signalstravel over each link at a speed of 108 meters per second. Assume that the link bandwidth on eachlink is 1Mbps. Let the file be broken down into 1000 packets each of size 1000 bits. Find the totalsum of transmission and propagation delays in transmitting the file from S to D?a)1005 msb)1010msc)3000 msd)3003 msCorrect answer is option 'A'. Can you explain this answer?.

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