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Q. No. 11 – 35 Carry One Mark Each
Q.
Consider an undirected random graph of eight vertices. The probability that there is an edge
between a pair of vertices is ½. What is the expected number of unordered cycles of length
three?
  • a)
    1/8
  • b)
    1
  • c)
    7
  • d)
    8
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Q. No. 11 – 35 Carry One Mark EachQ.Consider an undirected rando...
P(edge) =1/2
Number of ways we can choose the vertices out of 8 is
(Three edges in each cycle)
Expected number of unordered cycles of length 3 =  x (1/2)3 =7
 
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Q. No. 11 – 35 Carry One Mark EachQ.Consider an undirected random graph of eight vertices. The probability that there is an edgebetween a pair of vertices is ½. What is the expected number of unordered cycles of lengththree?a)1/8b)1c)7d)8Correct answer is option 'C'. Can you explain this answer?
Question Description
Q. No. 11 – 35 Carry One Mark EachQ.Consider an undirected random graph of eight vertices. The probability that there is an edgebetween a pair of vertices is ½. What is the expected number of unordered cycles of lengththree?a)1/8b)1c)7d)8Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Q. No. 11 – 35 Carry One Mark EachQ.Consider an undirected random graph of eight vertices. The probability that there is an edgebetween a pair of vertices is ½. What is the expected number of unordered cycles of lengththree?a)1/8b)1c)7d)8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q. No. 11 – 35 Carry One Mark EachQ.Consider an undirected random graph of eight vertices. The probability that there is an edgebetween a pair of vertices is ½. What is the expected number of unordered cycles of lengththree?a)1/8b)1c)7d)8Correct answer is option 'C'. Can you explain this answer?.
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