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The size of the data count register of a DMA controller is 16 bits. The processor needs to transfer a file of 29,154 kilobytes from disk to main memory. The memory is byte addressable. The minimum number of times the DMA controller needs to get the c
    Correct answer is '456'. Can you explain this answer?
    Verified Answer
    The size of the data count register of a DMA controller is 16 bits. Th...
    Size of data count register of the DMA controller = 16 bits
    Data that can be transferred in one go = 216 bytes = 64 kilobytes
    File size to be transferred = 29154 kilobytes
    So, number of times the DMA controller needs to get the control of the system bus from the processor to transfer the file from the disk to main memory = ceil(29154/64) = 456
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    The size of the data count register of a DMA controller is 16 bits. Th...
    Given Information:
    - The size of the data count register of a DMA controller is 16 bits.
    - The processor needs to transfer a file of 29,154 kilobytes from disk to main memory.
    - The memory is byte addressable.

    Calculations:
    To calculate the minimum number of times the DMA controller needs to get the correct answer, we need to consider the size of the data count register and the size of the file to be transferred.

    1. Converting file size to bytes:
    - 1 kilobyte = 1024 bytes.
    - Therefore, the file size in bytes = 29,154 kilobytes * 1024 = 29,154 * 1024 bytes.

    2. Calculating the maximum number of bytes the data count register can hold:
    - The data count register is 16 bits, which can hold a maximum value of 2^16 - 1 = 65,535.
    - Since the register counts in bytes, the maximum number of bytes it can hold is 65,535 bytes.

    3. Determining the minimum number of times the DMA controller needs to get the correct answer:
    - Divide the file size in bytes by the maximum number of bytes the data count register can hold.
    - Number of times = (File size in bytes) / (Maximum number of bytes in data count register).

    Final Answer:
    - Number of times = (29,154 * 1024 bytes) / 65,535 bytes = 456.

    Therefore, the minimum number of times the DMA controller needs to get the correct answer is 456.
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    The size of the data count register of a DMA controller is 16 bits. The processor needs to transfer a file of 29,154 kilobytes from disk to main memory. The memory is byte addressable. The minimum number of times the DMA controller needs to get the cCorrect answer is '456'. Can you explain this answer?
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