An infinitely long furnace of 0.5 m x 0.4 m cross-section is shown in the figure below. Consider all surfaces of the furnace to be black. The top and bottom walls are maintained at temperature T1 = T3 = 927oC while the side walls are at temperature T2 = T4 = 527oC. The view factor, F1-2 is 0.26. The net radiation heat loss or gain on side 1 is _____ W/m.Stefan-Boltzman constant = 5.67 x 10-8 W/m2-K4(Important - Enter only the numerical value in the answer)Correct answer is '24530.688'. Can you explain this answer?

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An infinitely long furnace of 0.5 m x 0.4 m cross-section is shown in the figure below. Consider all surfaces of the furnace to be black. The top and bottom walls are maintained at temperature T₁= T₃ = 927^oC while the side walls are at temperature T₂ = T₄ = 527^oC. The view factor, F_1-2 is 0.26. The net radiation heat loss or gain on side 1 is _____ W/m.

Stefan-Boltzman constant = 5.67 x 10^-8 W/m²-K⁴

(Important - Enter only the numerical value in the answer)

Correct answer is '24530.688'. Can you explain this answer?

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An infinitely long furnace of 0.5 m x 0.4 m cross-section is shown in ...

T₁ = 927^oC = 1200K,

T₂= 527^oC = 800K

F₁₂ = F₁₄ = 0.26

F₁₁ + F₁₂ + F₁₃ + F₁₄ = 1

F₁₃ = 0.48

Q = Q₁₂ + Q₁₃ + Q₁₄

Q₁₃ = 0 since the temperatures are same

Q = Q₁₂ + Q₁₄ = 2×σ_b×A×F₁₂(T₁⁴ - T₂⁴)

= 24530.688 Watt

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An infinitely long furnace of 0.5 m x 0.4 m cross-section is shown in the figure below. Consider all surfaces of the furnace to be black. The top and bottom walls are maintained at temperature T1 = T3 = 927oC while the side walls are at temperature T2 = T4 = 527oC. The view factor, F1-2 is 0.26. The net radiation heat loss or gain on side 1 is _____ W/m.Stefan-Boltzman constant = 5.67 x 10-8 W/m2-K4(Important - Enter only the numerical value in the answer)Correct answer is '24530.688'. Can you explain this answer?

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