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Pick out the correct statement with respect to[Mn(CN)6]3–:-
- a)It is sp3d2 hybridised and tetrahedral
- b)It is d2sp3 hybridised and octahedral
- c)It is dsp2 hybridised and square planar
- d)It is sp3d2 hybridised and octahedral
Correct answer is option 'B'. Can you explain this answer?
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Explanation:
The compound [Mn(CN)6]3- is an example of a coordination compound. In coordination compounds, a central metal ion or atom is surrounded by ligands, which are usually ions or molecules that donate electrons to the metal ion. The coordination number of a metal ion in a coordination compound refers to the number of ligands it is bonded to.
In the compound [Mn(CN)6]3-, the central metal ion is Mn, and it is bonded to six cyanide ligands (CN-).
Hybridization:
The hybridization of the central metal ion in a coordination compound can be determined by counting the number of ligands and lone pairs around the central metal ion. The hybridization of a central metal ion in a coordination compound is determined by the type of orbitals involved in bonding with the ligands.
In the case of [Mn(CN)6]3-, the Mn ion is bonded to six ligands (CN-) and has no lone pairs of electrons.
Octahedral Geometry:
The coordination number of Mn in [Mn(CN)6]3- is 6, indicating that it is bonded to six ligands. The most common geometry for a metal ion with a coordination number of 6 is octahedral. In an octahedral geometry, the ligands are arranged around the central metal ion in a symmetrical manner.
Therefore, the correct statement is option B: It is d2sp3 hybridized and octahedral. The Mn ion in [Mn(CN)6]3- is d2sp3 hybridized, meaning that it involves the mixing of one 3d orbital, two 4s orbitals, and three 4p orbitals to form six sp3 hybrid orbitals. These sp3 hybrid orbitals then overlap with the ligand orbitals to form six sigma bonds, resulting in an octahedral geometry.
The compound [Mn(CN)6]3- is an example of a coordination compound. In coordination compounds, a central metal ion or atom is surrounded by ligands, which are usually ions or molecules that donate electrons to the metal ion. The coordination number of a metal ion in a coordination compound refers to the number of ligands it is bonded to.
In the compound [Mn(CN)6]3-, the central metal ion is Mn, and it is bonded to six cyanide ligands (CN-).
Hybridization:
The hybridization of the central metal ion in a coordination compound can be determined by counting the number of ligands and lone pairs around the central metal ion. The hybridization of a central metal ion in a coordination compound is determined by the type of orbitals involved in bonding with the ligands.
In the case of [Mn(CN)6]3-, the Mn ion is bonded to six ligands (CN-) and has no lone pairs of electrons.
Octahedral Geometry:
The coordination number of Mn in [Mn(CN)6]3- is 6, indicating that it is bonded to six ligands. The most common geometry for a metal ion with a coordination number of 6 is octahedral. In an octahedral geometry, the ligands are arranged around the central metal ion in a symmetrical manner.
Therefore, the correct statement is option B: It is d2sp3 hybridized and octahedral. The Mn ion in [Mn(CN)6]3- is d2sp3 hybridized, meaning that it involves the mixing of one 3d orbital, two 4s orbitals, and three 4p orbitals to form six sp3 hybrid orbitals. These sp3 hybrid orbitals then overlap with the ligand orbitals to form six sigma bonds, resulting in an octahedral geometry.
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Pick out the correct statement with respect to[Mn(CN)6]3–:-a)It is sp3d2 hybridised and tetrahedralb)It is d2sp3 hybridised and octahedralc)It is dsp2 hybridised and square planard)It is sp3d2 hybridised and octahedralCorrect answer is option 'B'. Can you explain this answer?
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Pick out the correct statement with respect to[Mn(CN)6]3–:-a)It is sp3d2 hybridised and tetrahedralb)It is d2sp3 hybridised and octahedralc)It is dsp2 hybridised and square planard)It is sp3d2 hybridised and octahedralCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Pick out the correct statement with respect to[Mn(CN)6]3–:-a)It is sp3d2 hybridised and tetrahedralb)It is d2sp3 hybridised and octahedralc)It is dsp2 hybridised and square planard)It is sp3d2 hybridised and octahedralCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Pick out the correct statement with respect to[Mn(CN)6]3–:-a)It is sp3d2 hybridised and tetrahedralb)It is d2sp3 hybridised and octahedralc)It is dsp2 hybridised and square planard)It is sp3d2 hybridised and octahedralCorrect answer is option 'B'. Can you explain this answer?.
Pick out the correct statement with respect to[Mn(CN)6]3–:-a)It is sp3d2 hybridised and tetrahedralb)It is d2sp3 hybridised and octahedralc)It is dsp2 hybridised and square planard)It is sp3d2 hybridised and octahedralCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Pick out the correct statement with respect to[Mn(CN)6]3–:-a)It is sp3d2 hybridised and tetrahedralb)It is d2sp3 hybridised and octahedralc)It is dsp2 hybridised and square planard)It is sp3d2 hybridised and octahedralCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Pick out the correct statement with respect to[Mn(CN)6]3–:-a)It is sp3d2 hybridised and tetrahedralb)It is d2sp3 hybridised and octahedralc)It is dsp2 hybridised and square planard)It is sp3d2 hybridised and octahedralCorrect answer is option 'B'. Can you explain this answer?.
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