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A charge having q/m equal to 10^8 c/kg and with velocity 3×10^5 m/s enters into a uniform magnetic field B= 0.3 Tesla at an angle of 30 with direction of field. Then radius will be?
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A charge having q/m equal to 10^8 c/kg and with velocity 3×10^5 m/s en...
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A charge having q/m equal to 10^8 c/kg and with velocity 3×10^5 m/s en...
**Given information:**
- Charge-to-mass ratio (q/m) = 10^8 C/kg
- Velocity (v) = 3 × 10^5 m/s
- Magnetic field (B) = 0.3 Tesla
- Angle between the velocity and magnetic field (θ) = 30 degrees
**Explanation:**
1. The force experienced by a charged particle moving through a magnetic field is given by the equation: F = qvBsinθ, where q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and magnetic field.
2. The force experienced by the charged particle is centripetal in nature and is given by the equation: F = mv^2/r, where m is the mass of the charged particle and r is the radius of the circular path.
3. Equating the two forces, we have: qvBsinθ = mv^2/r
4. Rearranging the equation, we get: r = mv/(qBsinθ)
5. Substituting the given values, we have: r = (10^8 C/kg) × (3 × 10^5 m/s) / ((0.3 Tesla) × sin(30°))
6. Evaluating the expression, we get: r = (10^8 C/kg) × (3 × 10^5 m/s) / ((0.3 Tesla) × 0.5)
7. Simplifying further, we get: r = (10^8 C/kg) × (3 × 10^5 m/s) / (0.15 Tesla)
8. Multiplying the values, we get: r = 3 × 10^13 m^2/s^2
9. Simplifying further, we get: r = 3 × 10^13 m
**Answer:**
The radius of the charged particle's path is 3 × 10^13 meters.
Note: Please note that the equation used to calculate the radius assumes that the charged particle is moving in a uniform magnetic field and experiences a force perpendicular to its velocity.
- Charge-to-mass ratio (q/m) = 10^8 C/kg
- Velocity (v) = 3 × 10^5 m/s
- Magnetic field (B) = 0.3 Tesla
- Angle between the velocity and magnetic field (θ) = 30 degrees
**Explanation:**
1. The force experienced by a charged particle moving through a magnetic field is given by the equation: F = qvBsinθ, where q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and magnetic field.
2. The force experienced by the charged particle is centripetal in nature and is given by the equation: F = mv^2/r, where m is the mass of the charged particle and r is the radius of the circular path.
3. Equating the two forces, we have: qvBsinθ = mv^2/r
4. Rearranging the equation, we get: r = mv/(qBsinθ)
5. Substituting the given values, we have: r = (10^8 C/kg) × (3 × 10^5 m/s) / ((0.3 Tesla) × sin(30°))
6. Evaluating the expression, we get: r = (10^8 C/kg) × (3 × 10^5 m/s) / ((0.3 Tesla) × 0.5)
7. Simplifying further, we get: r = (10^8 C/kg) × (3 × 10^5 m/s) / (0.15 Tesla)
8. Multiplying the values, we get: r = 3 × 10^13 m^2/s^2
9. Simplifying further, we get: r = 3 × 10^13 m
**Answer:**
The radius of the charged particle's path is 3 × 10^13 meters.
Note: Please note that the equation used to calculate the radius assumes that the charged particle is moving in a uniform magnetic field and experiences a force perpendicular to its velocity.
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A charge having q/m equal to 10^8 c/kg and with velocity 3×10^5 m/s enters into a uniform magnetic field B= 0.3 Tesla at an angle of 30 with direction of field. Then radius will be?
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A charge having q/m equal to 10^8 c/kg and with velocity 3×10^5 m/s enters into a uniform magnetic field B= 0.3 Tesla at an angle of 30 with direction of field. Then radius will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A charge having q/m equal to 10^8 c/kg and with velocity 3×10^5 m/s enters into a uniform magnetic field B= 0.3 Tesla at an angle of 30 with direction of field. Then radius will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A charge having q/m equal to 10^8 c/kg and with velocity 3×10^5 m/s enters into a uniform magnetic field B= 0.3 Tesla at an angle of 30 with direction of field. Then radius will be?.
A charge having q/m equal to 10^8 c/kg and with velocity 3×10^5 m/s enters into a uniform magnetic field B= 0.3 Tesla at an angle of 30 with direction of field. Then radius will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A charge having q/m equal to 10^8 c/kg and with velocity 3×10^5 m/s enters into a uniform magnetic field B= 0.3 Tesla at an angle of 30 with direction of field. Then radius will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A charge having q/m equal to 10^8 c/kg and with velocity 3×10^5 m/s enters into a uniform magnetic field B= 0.3 Tesla at an angle of 30 with direction of field. Then radius will be?.
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