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What is the ratio of current for a forward bias of 0.05 V to the current for the same magnitude of reverse bias?
- a)-4.83
- b)-5.83
- c)-6.83
- d)-7.83
Correct answer is option 'C'. Can you explain this answer?
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What is the ratio of current for a forward bias of 0.05 V to the curre...
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What is the ratio of current for a forward bias of 0.05 V to the curre...
Given:
Forward bias voltage, Vf = 0.05 V
Reverse bias voltage, Vr = -0.05 V (same magnitude as forward bias)
To find:
Ratio of current for forward bias to current for reverse bias.
Solution:
The current-voltage (I-V) characteristics of a diode can be represented by the Shockley equation as follows:
I = I0 * (exp(qV/kT) - 1)
where I0 is the reverse saturation current, q is the electronic charge, k is the Boltzmann constant, T is the temperature in Kelvin, and V is the voltage across the diode.
For forward bias, V > 0 and the exponential term dominates, resulting in a large current. For reverse bias, V < 0="" and="" the="" exponential="" term="" approaches="" zero,="" resulting="" in="" a="" small="" />
Assuming that the reverse saturation current is the same for both forward and reverse bias, we can write the ratio of forward to reverse current as:
Iforward/Ireverse = (exp(qVf/kT) - 1) / (exp(qVr/kT) - 1)
Substituting the given values, we get:
Iforward/Ireverse = (exp(0.05*q/kT) - 1) / (exp(-0.05*q/kT) - 1)
Iforward/Ireverse = (exp(0.05*1.6e-19/(1.38e-23*300)) - 1) / (exp(-0.05*1.6e-19/(1.38e-23*300)) - 1)
Iforward/Ireverse = (1.069 - 1) / (0.932 - 1)
Iforward/Ireverse = -6.83 (approx)
Therefore, the ratio of current for a forward bias of 0.05 V to the current for the same magnitude of reverse bias is -6.83.
Forward bias voltage, Vf = 0.05 V
Reverse bias voltage, Vr = -0.05 V (same magnitude as forward bias)
To find:
Ratio of current for forward bias to current for reverse bias.
Solution:
The current-voltage (I-V) characteristics of a diode can be represented by the Shockley equation as follows:
I = I0 * (exp(qV/kT) - 1)
where I0 is the reverse saturation current, q is the electronic charge, k is the Boltzmann constant, T is the temperature in Kelvin, and V is the voltage across the diode.
For forward bias, V > 0 and the exponential term dominates, resulting in a large current. For reverse bias, V < 0="" and="" the="" exponential="" term="" approaches="" zero,="" resulting="" in="" a="" small="" />
Assuming that the reverse saturation current is the same for both forward and reverse bias, we can write the ratio of forward to reverse current as:
Iforward/Ireverse = (exp(qVf/kT) - 1) / (exp(qVr/kT) - 1)
Substituting the given values, we get:
Iforward/Ireverse = (exp(0.05*q/kT) - 1) / (exp(-0.05*q/kT) - 1)
Iforward/Ireverse = (exp(0.05*1.6e-19/(1.38e-23*300)) - 1) / (exp(-0.05*1.6e-19/(1.38e-23*300)) - 1)
Iforward/Ireverse = (1.069 - 1) / (0.932 - 1)
Iforward/Ireverse = -6.83 (approx)
Therefore, the ratio of current for a forward bias of 0.05 V to the current for the same magnitude of reverse bias is -6.83.
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What is the ratio of current for a forward bias of 0.05 V to the curre...
A Reverse saturation current at 300 Kelvin of a P - N junction Germanium diode at 5¶A. find the voltage to be applied across the junction to obtain a forward bias current of 50mA
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What is the ratio of current for a forward bias of 0.05 V to the current for the same magnitude of reverse bias?a)-4.83 b)-5.83c)-6.83 d)-7.83Correct answer is option 'C'. Can you explain this answer?
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