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What will the output of the following C code ?
#include <stdio.h>
int main()
{ int i=2, j=2;
while (i+1 ? --i : j++)
printf("%d",i);
return 0;
}
int main()
{ int i=2, j=2;
while (i+1 ? --i : j++)
printf("%d",i);
return 0;
}
- a)1
- b)2
- c)3
- d)4
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
What will the output of the following C code ?#include <stdio.h>...
Consider the while loop condition => i + 1 ? --i : j++
In first iteration : i + 1 = 3 (true)
So ternary operator will return --i i.e. 1, condition part is 1 means true
so while condition is true.
Hence printf statement will print 1 In second iteration : i + 1 =2 (true)
So ternary operator will return --i i.e 0, condition part is 0 means false
so while condition is false.
Hence program control will come out of the while loop.
In first iteration : i + 1 = 3 (true)
So ternary operator will return --i i.e. 1, condition part is 1 means true
so while condition is true.
Hence printf statement will print 1 In second iteration : i + 1 =2 (true)
So ternary operator will return --i i.e 0, condition part is 0 means false
so while condition is false.
Hence program control will come out of the while loop.
Most Upvoted Answer
What will the output of the following C code ?#include <stdio.h>...
Explanation:
- The code provided is a C program that uses a while loop to iterate until a certain condition is met.
- Initially, the variables i and j are both set to 2.
- In the while loop condition, the expression i+1 ? --i : j++ is evaluated.
- If i+1 is true (non-zero), then --i is executed, which decrements the value of i by 1.
- If i+1 is false (zero), then j++ is executed, which increments the value of j by 1.
- The printf statement inside the loop prints the value of i after each iteration.
Execution:
- In the first iteration, i+1 is equal to 3 (true), so --i is executed, decrementing i to 1.
- In the second iteration, i+1 is equal to 2 (true), so --i is executed again, decrementing i to 0.
- In the third iteration, i+1 is equal to 1 (true), so --i is executed again, decrementing i to -1.
- Since i+1 is now false (zero), the loop exits.
Output:
- The output of the program will be 1, as the loop iterates and decrements the value of i until the condition i+1 is false.
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