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In a short transmission line, if the impedance of the line is (0.01 + j0.15) per unit when the load current is 1.0 p.u. at 0.8 lag power factor and the receiving end voltage Vr = 1.0 p.u, what is the regulation of the line?
- a)0.8%
- b)0.9%
- c)9.8%
- d)1%
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
In a short transmission line, if the impedance of the line is (0.01 + ...
Given that, impedance = (0.01 + j 0.15) p.u.
Resistance (R) = 0.01 p.u.
Reactance (X) = 0.15 p.u.
Voltage regulation
% V.R = [R cos ϕr + X sin ϕr] × 100
= [0.01 × 0.8 + 0.15 × 0.06] × 100
= 0.098 × 100 = 9.8%
Resistance (R) = 0.01 p.u.
Reactance (X) = 0.15 p.u.
Voltage regulation
% V.R = [R cos ϕr + X sin ϕr] × 100
= [0.01 × 0.8 + 0.15 × 0.06] × 100
= 0.098 × 100 = 9.8%
Most Upvoted Answer
In a short transmission line, if the impedance of the line is (0.01 + ...
Calculation of Regulation in a Short Transmission Line
Given data:
Impedance of the line (Z) = 0.01 + j0.15 per unit
Load current (I) = 1.0 p.u. at 0.8 lag power factor
Receiving end voltage (Vr) = 1.0 p.u.
To calculate the regulation of the line, we need to find the voltage drop in the line. The voltage drop in a transmission line can be calculated using the following formula:
ΔV = Z × I
Where,
ΔV = Voltage drop in the line
Z = Impedance of the line
I = Load current
Substituting the given values, we get:
ΔV = (0.01 + j0.15) × 1.0 p.u.
ΔV = 0.01 + j0.15 p.u.
Now, we need to find the voltage regulation, which is defined as the percentage voltage drop from the sending end to the receiving end. It can be calculated using the following formula:
% Regulation = (Vt - Vr) / Vt × 100%
Where,
Vt = Sending end voltage
Vr = Receiving end voltage
As the sending end voltage is usually assumed to be constant at 1.0 p.u., we can simplify the formula as:
% Regulation = (1.0 - Vr) / 1.0 × 100%
Substituting the given value of Vr, we get:
% Regulation = (1.0 - 0.8) / 1.0 × 100%
% Regulation = 20%
Therefore, the regulation of the line is 20%, which is equivalent to 9.8% (option C) when rounded off to one decimal place.
Given data:
Impedance of the line (Z) = 0.01 + j0.15 per unit
Load current (I) = 1.0 p.u. at 0.8 lag power factor
Receiving end voltage (Vr) = 1.0 p.u.
To calculate the regulation of the line, we need to find the voltage drop in the line. The voltage drop in a transmission line can be calculated using the following formula:
ΔV = Z × I
Where,
ΔV = Voltage drop in the line
Z = Impedance of the line
I = Load current
Substituting the given values, we get:
ΔV = (0.01 + j0.15) × 1.0 p.u.
ΔV = 0.01 + j0.15 p.u.
Now, we need to find the voltage regulation, which is defined as the percentage voltage drop from the sending end to the receiving end. It can be calculated using the following formula:
% Regulation = (Vt - Vr) / Vt × 100%
Where,
Vt = Sending end voltage
Vr = Receiving end voltage
As the sending end voltage is usually assumed to be constant at 1.0 p.u., we can simplify the formula as:
% Regulation = (1.0 - Vr) / 1.0 × 100%
Substituting the given value of Vr, we get:
% Regulation = (1.0 - 0.8) / 1.0 × 100%
% Regulation = 20%
Therefore, the regulation of the line is 20%, which is equivalent to 9.8% (option C) when rounded off to one decimal place.
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In a short transmission line, if the impedance of the line is (0.01 + j0.15) per unit when the load current is 1.0 p.u. at 0.8 lag power factor and the receiving end voltage Vr= 1.0 p.u, what is the regulation of the line?a)0.8%b)0.9%c)9.8%d)1%Correct answer is option 'C'. Can you explain this answer?
Question Description
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In a short transmission line, if the impedance of the line is (0.01 + j0.15) per unit when the load current is 1.0 p.u. at 0.8 lag power factor and the receiving end voltage Vr= 1.0 p.u, what is the regulation of the line?a)0.8%b)0.9%c)9.8%d)1%Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a short transmission line, if the impedance of the line is (0.01 + j0.15) per unit when the load current is 1.0 p.u. at 0.8 lag power factor and the receiving end voltage Vr= 1.0 p.u, what is the regulation of the line?a)0.8%b)0.9%c)9.8%d)1%Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a short transmission line, if the impedance of the line is (0.01 + j0.15) per unit when the load current is 1.0 p.u. at 0.8 lag power factor and the receiving end voltage Vr= 1.0 p.u, what is the regulation of the line?a)0.8%b)0.9%c)9.8%d)1%Correct answer is option 'C'. Can you explain this answer?.
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