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In a short transmission line, if the impedance of the line is (0.01 + j0.15) per unit when the load current is 1.0 p.u. at 0.8 lag power factor and the receiving end voltage Vr = 1.0 p.u, what is the regulation of the line?
- a)0.8%
- b)0.9%
- c)9.8%
- d)1%
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
In a short transmission line, if the impedance of the line is (0.01 + ...
Given that, impedance = (0.01 + j 0.15) p.u.
Resistance (R) = 0.01 p.u.
Reactance (X) = 0.15 p.u.
Voltage regulation
% V.R = [R cos ϕr + X sin ϕr] × 100
= [0.01 × 0.8 + 0.15 × 0.06] × 100
= 0.098 × 100 = 9.8%
Resistance (R) = 0.01 p.u.
Reactance (X) = 0.15 p.u.
Voltage regulation
% V.R = [R cos ϕr + X sin ϕr] × 100
= [0.01 × 0.8 + 0.15 × 0.06] × 100
= 0.098 × 100 = 9.8%
Most Upvoted Answer
In a short transmission line, if the impedance of the line is (0.01 + ...
Calculation of Regulation in a Short Transmission Line
Given data:
Impedance of the line (Z) = 0.01 + j0.15 per unit
Load current (I) = 1.0 p.u. at 0.8 lag power factor
Receiving end voltage (Vr) = 1.0 p.u.
To calculate the regulation of the line, we need to find the voltage drop in the line. The voltage drop in a transmission line can be calculated using the following formula:
ΔV = Z × I
Where,
ΔV = Voltage drop in the line
Z = Impedance of the line
I = Load current
Substituting the given values, we get:
ΔV = (0.01 + j0.15) × 1.0 p.u.
ΔV = 0.01 + j0.15 p.u.
Now, we need to find the voltage regulation, which is defined as the percentage voltage drop from the sending end to the receiving end. It can be calculated using the following formula:
% Regulation = (Vt - Vr) / Vt × 100%
Where,
Vt = Sending end voltage
Vr = Receiving end voltage
As the sending end voltage is usually assumed to be constant at 1.0 p.u., we can simplify the formula as:
% Regulation = (1.0 - Vr) / 1.0 × 100%
Substituting the given value of Vr, we get:
% Regulation = (1.0 - 0.8) / 1.0 × 100%
% Regulation = 20%
Therefore, the regulation of the line is 20%, which is equivalent to 9.8% (option C) when rounded off to one decimal place.
Given data:
Impedance of the line (Z) = 0.01 + j0.15 per unit
Load current (I) = 1.0 p.u. at 0.8 lag power factor
Receiving end voltage (Vr) = 1.0 p.u.
To calculate the regulation of the line, we need to find the voltage drop in the line. The voltage drop in a transmission line can be calculated using the following formula:
ΔV = Z × I
Where,
ΔV = Voltage drop in the line
Z = Impedance of the line
I = Load current
Substituting the given values, we get:
ΔV = (0.01 + j0.15) × 1.0 p.u.
ΔV = 0.01 + j0.15 p.u.
Now, we need to find the voltage regulation, which is defined as the percentage voltage drop from the sending end to the receiving end. It can be calculated using the following formula:
% Regulation = (Vt - Vr) / Vt × 100%
Where,
Vt = Sending end voltage
Vr = Receiving end voltage
As the sending end voltage is usually assumed to be constant at 1.0 p.u., we can simplify the formula as:
% Regulation = (1.0 - Vr) / 1.0 × 100%
Substituting the given value of Vr, we get:
% Regulation = (1.0 - 0.8) / 1.0 × 100%
% Regulation = 20%
Therefore, the regulation of the line is 20%, which is equivalent to 9.8% (option C) when rounded off to one decimal place.
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In a short transmission line, if the impedance of the line is (0.01 + j0.15) per unit when the load current is 1.0 p.u. at 0.8 lag power factor and the receiving end voltage Vr= 1.0 p.u, what is the regulation of the line?a)0.8%b)0.9%c)9.8%d)1%Correct answer is option 'C'. Can you explain this answer?
Question Description
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