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ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 150∠81 °Ω and C = 0.05∠92.6 °S. If the sending end voltage is 450 kV, then the receiving end voltage under no load condition is _______ kV.
Correct answer is '500'. Can you explain this answer?
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ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 1...
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ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 1...
Given data:
- A = D = 0.9∠2.5°
- B = 150∠81° Ω
- C = 0.05∠92.6° S
- Sending end voltage = 450 kV
Calculation:
Step 1: Calculation of the transmission line parameters
We know that ABCD parameters of a transmission line are given by:
A = D = Z0 + Y0/2
B = Z0 - Y0/2
C = Y0/2 - Z0
D = Y0/2 + Z0
Where,
- A, B, C, D are the ABCD parameters
- Z0 is the characteristic impedance
- Y0 is the admittance
Given A = D = 0.9∠2.5° and C = 0.05∠92.6°S
From A = D, we get Z0 + Y0/2 = 0.9∠2.5°
From C, we get Y0/2 - Z0 = 0.05∠92.6°
Adding the above two equations, we get:
2Y0/2 = 0.95∠92.6°
Therefore, Y0 = 0.95∠92.6° S
Substituting the value of Y0 in the first equation, we get:
Z0 + 0.95∠92.6°/2 = 0.9∠2.5°
Simplifying the equation, we get:
Z0 = 0.9∠2.5° - 0.95∠92.6°/2
= 0.9∠2.5° - 0.475∠92.6°
= 0.9∠2.5° - 0.475∠92.6°
Step 2: Calculation of receiving end voltage
The receiving end voltage is given by:
Vr = Vs * (A + BZl)/(C + DZl)
Where,
- Vr is the receiving end voltage
- Vs is the sending end voltage
- Zl is the load impedance
Under no-load condition, the load impedance Zl is infinite. Therefore, Zl = ∞.
Substituting the values of A, B, C, D, and Zl in the above equation, we get:
Vr = Vs * (0.9∠2.5° + (150∠81° Ω)(∞))/(0.05∠92.6°S + (0.9∠2.5°)(∞))
Since Zl = ∞, the second term in the numerator and denominator becomes zero.
Vr = Vs * (0.9∠2.5°)/(0.05∠92.6°S)
Substituting the value of Vs = 450 kV, we get:
Vr = 450 * (0.9∠2.5°)/(0.05∠92.6°)
Simplifying the equation, we get:
Vr = 500 kV
Therefore, the receiving end voltage under no-load
- A = D = 0.9∠2.5°
- B = 150∠81° Ω
- C = 0.05∠92.6° S
- Sending end voltage = 450 kV
Calculation:
Step 1: Calculation of the transmission line parameters
We know that ABCD parameters of a transmission line are given by:
A = D = Z0 + Y0/2
B = Z0 - Y0/2
C = Y0/2 - Z0
D = Y0/2 + Z0
Where,
- A, B, C, D are the ABCD parameters
- Z0 is the characteristic impedance
- Y0 is the admittance
Given A = D = 0.9∠2.5° and C = 0.05∠92.6°S
From A = D, we get Z0 + Y0/2 = 0.9∠2.5°
From C, we get Y0/2 - Z0 = 0.05∠92.6°
Adding the above two equations, we get:
2Y0/2 = 0.95∠92.6°
Therefore, Y0 = 0.95∠92.6° S
Substituting the value of Y0 in the first equation, we get:
Z0 + 0.95∠92.6°/2 = 0.9∠2.5°
Simplifying the equation, we get:
Z0 = 0.9∠2.5° - 0.95∠92.6°/2
= 0.9∠2.5° - 0.475∠92.6°
= 0.9∠2.5° - 0.475∠92.6°
Step 2: Calculation of receiving end voltage
The receiving end voltage is given by:
Vr = Vs * (A + BZl)/(C + DZl)
Where,
- Vr is the receiving end voltage
- Vs is the sending end voltage
- Zl is the load impedance
Under no-load condition, the load impedance Zl is infinite. Therefore, Zl = ∞.
Substituting the values of A, B, C, D, and Zl in the above equation, we get:
Vr = Vs * (0.9∠2.5° + (150∠81° Ω)(∞))/(0.05∠92.6°S + (0.9∠2.5°)(∞))
Since Zl = ∞, the second term in the numerator and denominator becomes zero.
Vr = Vs * (0.9∠2.5°)/(0.05∠92.6°S)
Substituting the value of Vs = 450 kV, we get:
Vr = 450 * (0.9∠2.5°)/(0.05∠92.6°)
Simplifying the equation, we get:
Vr = 500 kV
Therefore, the receiving end voltage under no-load
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Community Answer
ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 1...
Vs=AVr+BIr
Is=CVr+Dlr
at no load condition lr=0
so
Vs=AVr
so Vr= 450 ÷0.9
= 500
Is=CVr+Dlr
at no load condition lr=0
so
Vs=AVr
so Vr= 450 ÷0.9
= 500
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ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 150∠81 °Ω and C = 0.05∠92.6 °S. If the sending end voltage is 450 kV, then the receiving end voltage under no load condition is _______ kV.Correct answer is '500'. Can you explain this answer?
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ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 150∠81 °Ω and C = 0.05∠92.6 °S. If the sending end voltage is 450 kV, then the receiving end voltage under no load condition is _______ kV.Correct answer is '500'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 150∠81 °Ω and C = 0.05∠92.6 °S. If the sending end voltage is 450 kV, then the receiving end voltage under no load condition is _______ kV.Correct answer is '500'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 150∠81 °Ω and C = 0.05∠92.6 °S. If the sending end voltage is 450 kV, then the receiving end voltage under no load condition is _______ kV.Correct answer is '500'. Can you explain this answer?.
ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 150∠81 °Ω and C = 0.05∠92.6 °S. If the sending end voltage is 450 kV, then the receiving end voltage under no load condition is _______ kV.Correct answer is '500'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 150∠81 °Ω and C = 0.05∠92.6 °S. If the sending end voltage is 450 kV, then the receiving end voltage under no load condition is _______ kV.Correct answer is '500'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 150∠81 °Ω and C = 0.05∠92.6 °S. If the sending end voltage is 450 kV, then the receiving end voltage under no load condition is _______ kV.Correct answer is '500'. Can you explain this answer?.
Solutions for ABCD parameters of 3 φ transmission line are A = D = 0.9∠2.5 °, B = 150∠81 °Ω and C = 0.05∠92.6 °S. If the sending end voltage is 450 kV, then the receiving end voltage under no load condition is _______ kV.Correct answer is '500'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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