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A 60 μA meter has a resistance of 100 ohms. If the meter has to measure 100 mA, then the value of shunt resistance and the current through shunt respectively are
- a)0.06 Ω, 99.94 mA
- b)0.08 Ω, 99.2 mA
- c)0.8 Ω, 99.2 mA
- d)0.6 Ω, 99.4 mA
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A 60 μA meter has a resistance of 100 ohms. If the meter has to mea...
Given that, current through meter (Im) = 60 μA
Total required current (I) = 100 mA
Meter resistance (Rm) = 100 Ω
Current flows though shunt resistance
Ish = I - Im
= 100 × 10‑3 – 60 × 10-6
= (100 – 0.06) × 10-3
= 99.94 mA
Total required current (I) = 100 mA
Meter resistance (Rm) = 100 Ω
Current flows though shunt resistance
Ish = I - Im
= 100 × 10‑3 – 60 × 10-6
= (100 – 0.06) × 10-3
= 99.94 mA
Most Upvoted Answer
A 60 μA meter has a resistance of 100 ohms. If the meter has to mea...
Calculating the shunt resistance and current through shunt:
- Given values:
- Meter current (Im) = 60 μA = 0.06 mA
- Meter resistance (Rm) = 100 ohms
- Required current to be measured (I) = 100 mA
- To calculate the shunt resistance (Rs) and current through shunt (Is), we can use the formula for a parallel circuit:
- 1/R = 1/Rm + 1/Rs
- I = Im + Is
- Substituting the given values into the formulas:
- 1/R = 1/100 + 1/Rs
- 100 mA = 0.06 mA + Is
- Solving the equations:
- 1/R = 1/100 + 1/Rs
=> 1/R = (Rs + 100)/(100 * Rs)
=> R = 100 * Rs / (Rs + 100)
=> Rs = 100 * R / (100 - R)
=> Rs = 100 * 100 / (100 - 100)
=> Rs = 100 * 100 / 100
=> Rs = 100 ohms
- 100 mA = 0.06 mA + Is
=> Is = 100 - 0.06
=> Is = 99.94 mA
Therefore, the shunt resistance is 0.06 ohms and the current through the shunt is 99.94 mA, which corresponds to option A.
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A 60 μA meter has a resistance of 100 ohms. If the meter has to measure 100 mA, then the value of shunt resistance and the current through shunt respectively area)0.06 Ω, 99.94 mAb)0.08 Ω, 99.2 mAc)0.8 Ω, 99.2 mAd)0.6 Ω, 99.4 mACorrect answer is option 'A'. Can you explain this answer?
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