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A single-phase half wave converter is operated from 220 V, 50 Hz source and the load resistance R = 12 Ω, For the firing angle delay 60° determine The RMS Voltage.
    Correct answer is between '138,142'. Can you explain this answer?
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    A single-phase half wave converter is operated from 220 V, 50 Hz sourc...
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    A single-phase half wave converter is operated from 220 V, 50 Hz sourc...
    The output voltage of a single-phase half wave converter is given by:

    Vout = Vmax * sin(α)

    Where Vmax is the maximum voltage of the input AC source and α is the firing angle of the thyristor. The firing angle determines the point in each half cycle at which the thyristor is triggered and allows current to flow through the load.

    For a half wave converter, the thyristor is triggered at the start of each positive half cycle of the input voltage. Therefore, α = 0 for this circuit.

    The maximum voltage of the input AC source is 220 V. Therefore, the output voltage of the half wave converter is:

    Vout = Vmax * sin(α) = 220 * sin(0) = 0 V

    This means that there is no output voltage for this circuit, and the load resistance R does not matter.

    It is worth noting that a half wave converter is not an efficient or practical way to convert AC power to DC power, as it only utilizes half of the input voltage and causes significant ripple in the output voltage. Other types of converters, such as full wave and bridge rectifiers, are commonly used for AC to DC conversion.
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    A single-phase half wave converter is operated from 220 V, 50 Hz source and the load resistance R = 12 Ω, For the firing angle delay 60° determine The RMS Voltage.Correct answer is between '138,142'. Can you explain this answer?
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