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Water flows through a tube of diameter 25mm at an average velocity 1 m/sec. The properties of water ρ = 1000 kg/m3, μ = 6x 10-4 N-s/m2 , K= 0.625 W/mK, Pr= 4, Given Dittus – Boelter equation, Nu =0.023Re0.8 Prn and constant heat flux Nu = 3.66. What is Nusset number when fluid is cooling?
Correct answer is between '172,174'. Can you explain this answer?
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Water flows through a tube of diameter 25mm at an average velocity 1 m...
Given, Pr = 4, fluid is cooling so, n= 0.3
So the flow is turbulent, we have to use Dittus- Boelter equation i.e
So the flow is turbulent, we have to use Dittus- Boelter equation i.e
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Water flows through a tube of diameter 25mm at an average velocity 1 m...
The properties of water that are relevant in this scenario include its density, viscosity, and flow rate.
1. Density: The density of water is approximately 1000 kg/m^3. This property determines the mass of water flowing through the tube.
2. Viscosity: The viscosity of water is relatively low compared to other liquids. It is approximately 0.001 Pa·s at 20°C. Viscosity affects the resistance to flow and determines the pressure drop along the tube.
3. Flow rate: The flow rate of water is the volume of water passing through a given point per unit time. In this case, the flow rate can be calculated using the formula Q = A * V, where Q is the flow rate, A is the cross-sectional area of the tube, and V is the average velocity of water. In this scenario, the diameter of the tube is given as 25mm, so the radius is 12.5mm or 0.0125m. The cross-sectional area can be calculated as A = π * r^2 = π * (0.0125)^2 = 0.00049087 m^2. Therefore, the flow rate is Q = 0.00049087 m^2 * 1 m/sec = 0.00049087 m^3/sec.
These properties of water are important in understanding the behavior of water flow through the tube and can be used to analyze and design fluid systems.
1. Density: The density of water is approximately 1000 kg/m^3. This property determines the mass of water flowing through the tube.
2. Viscosity: The viscosity of water is relatively low compared to other liquids. It is approximately 0.001 Pa·s at 20°C. Viscosity affects the resistance to flow and determines the pressure drop along the tube.
3. Flow rate: The flow rate of water is the volume of water passing through a given point per unit time. In this case, the flow rate can be calculated using the formula Q = A * V, where Q is the flow rate, A is the cross-sectional area of the tube, and V is the average velocity of water. In this scenario, the diameter of the tube is given as 25mm, so the radius is 12.5mm or 0.0125m. The cross-sectional area can be calculated as A = π * r^2 = π * (0.0125)^2 = 0.00049087 m^2. Therefore, the flow rate is Q = 0.00049087 m^2 * 1 m/sec = 0.00049087 m^3/sec.
These properties of water are important in understanding the behavior of water flow through the tube and can be used to analyze and design fluid systems.
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Water flows through a tube of diameter 25mm at an average velocity 1 m/sec. The properties of waterρ= 1000 kg/m3,μ= 6x 10-4N-s/m2, K= 0.625 W/mK, Pr= 4, Given Dittus – Boelter equation, Nu=0.023Re0.8Prnand constant heat flux Nu= 3.66. What is Nusset number when fluid is cooling?Correct answer is between '172,174'. Can you explain this answer?
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Water flows through a tube of diameter 25mm at an average velocity 1 m/sec. The properties of waterρ= 1000 kg/m3,μ= 6x 10-4N-s/m2, K= 0.625 W/mK, Pr= 4, Given Dittus – Boelter equation, Nu=0.023Re0.8Prnand constant heat flux Nu= 3.66. What is Nusset number when fluid is cooling?Correct answer is between '172,174'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Water flows through a tube of diameter 25mm at an average velocity 1 m/sec. The properties of waterρ= 1000 kg/m3,μ= 6x 10-4N-s/m2, K= 0.625 W/mK, Pr= 4, Given Dittus – Boelter equation, Nu=0.023Re0.8Prnand constant heat flux Nu= 3.66. What is Nusset number when fluid is cooling?Correct answer is between '172,174'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Water flows through a tube of diameter 25mm at an average velocity 1 m/sec. The properties of waterρ= 1000 kg/m3,μ= 6x 10-4N-s/m2, K= 0.625 W/mK, Pr= 4, Given Dittus – Boelter equation, Nu=0.023Re0.8Prnand constant heat flux Nu= 3.66. What is Nusset number when fluid is cooling?Correct answer is between '172,174'. Can you explain this answer?.
Water flows through a tube of diameter 25mm at an average velocity 1 m/sec. The properties of waterρ= 1000 kg/m3,μ= 6x 10-4N-s/m2, K= 0.625 W/mK, Pr= 4, Given Dittus – Boelter equation, Nu=0.023Re0.8Prnand constant heat flux Nu= 3.66. What is Nusset number when fluid is cooling?Correct answer is between '172,174'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Water flows through a tube of diameter 25mm at an average velocity 1 m/sec. The properties of waterρ= 1000 kg/m3,μ= 6x 10-4N-s/m2, K= 0.625 W/mK, Pr= 4, Given Dittus – Boelter equation, Nu=0.023Re0.8Prnand constant heat flux Nu= 3.66. What is Nusset number when fluid is cooling?Correct answer is between '172,174'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Water flows through a tube of diameter 25mm at an average velocity 1 m/sec. The properties of waterρ= 1000 kg/m3,μ= 6x 10-4N-s/m2, K= 0.625 W/mK, Pr= 4, Given Dittus – Boelter equation, Nu=0.023Re0.8Prnand constant heat flux Nu= 3.66. What is Nusset number when fluid is cooling?Correct answer is between '172,174'. Can you explain this answer?.
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