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Consider the given SDT which will be executed in connection with a bottom-up parser. For the input babbba, what will be the final output?
S →aS { print “x”}
S →bS { print “y”}
S →a { print “z”}
S →b { print “z”}
- a)zxyyyx
- b)zyxxxy
- c)zyyyxy
- d)zxxxyx
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Consider the given SDT which will be executed in connection with a bot...
To determine the final output for the input "babbba" using the given Syntax Directed Translation (SDT) rules executed in connection with a bottom-up parser, we need to perform the following steps:
1. **Parse the input string "babbba" using the given grammar rules**:
- S →aS { print "x" }
- S →bS { print "y" }
- S →a { print "z" }
- S →b { print "z" }
- S →aS { print "x" }
- S →bS { print "y" }
- S →a { print "z" }
- S →b { print "z" }
2. **Generate the corresponding parse tree**:
- Starting from the bottom, recognize the terminals and apply the rules in reverse to form the non-terminals.
- Starting from the bottom, recognize the terminals and apply the rules in reverse to form the non-terminals.
3. **Apply the actions associated with the production rules in the order they are reduced during parsing**.
### Step-by-step Parsing:
1. **Input**: babbba
2. **Rightmost Derivation**:
- Recognize "b" and reduce using \( S \rightarrow b \) { print "z" }
- Output: "z"
- Now, the string becomes: babbbS
- Recognize "b" and reduce using \( S \rightarrow b \) { print "z" }
- Output: "z"
- Now, the string becomes: babbbS
- Recognize "a" and reduce using \( S \rightarrow aS \) { print "x" }
- Output: "z" (already from previous step) + "x"
- Now, the string becomes: babbS
- Output: "z" (already from previous step) + "x"
- Now, the string becomes: babbS
- Recognize "b" and reduce using \( S \rightarrow bS \) { print "y" }
- Output: "zx" + "y"
- Now, the string becomes: babS
- Output: "zx" + "y"
- Now, the string becomes: babS
- Recognize "b" and reduce using \( S \rightarrow bS \) { print "y" }
- Output: "zxy" + "y"
- Now, the string becomes: baS
- Output: "zxy" + "y"
- Now, the string becomes: baS
- Recognize "a" and reduce using \( S \rightarrow aS \) { print "x" }
- Output: "zxyy" + "x"
- Now, the string becomes: bS
- Output: "zxyy" + "x"
- Now, the string becomes: bS
- Recognize "b" and reduce using \( S \rightarrow bS \) { print "y" }
- Output: "zxyyx" + "y"
- Now, the string becomes: S
- Output: "zxyyx" + "y"
- Now, the string becomes: S
### Final Output:
- Combining all the prints together in the order of reductions, we get "zyyyxy".
- Combining all the prints together in the order of reductions, we get "zyyyxy".
Thus, the final output for the input "babbba" is:
**3. zyyyxy**
Most Upvoted Answer
Consider the given SDT which will be executed in connection with a bot...
Understanding the Syntax Directed Translation (SDT)
In the given SDT for the grammar, we have rules for the productions of S that also include printing certain characters based on the production rules used.
Production Rules
- S → aS { print "x"}
- S → bS { print "y"}
- S → a { print "z"}
- S → b { print "z"}
Input String: babbba
We will process the input "babbba" using a bottom-up parsing approach:
1. Parsing Steps:
- The input starts with 'b'. According to the rules, S can derive bS, so we apply that rule.
- After the first 'b', we have "abbba".
- Again, we can apply the rule S → bS for the second 'b', resulting in "abbb".
- Continue this process:
- S → bS for the third 'b', leading to "ab".
- S → aS for the 'a', resulting in "b".
2. Final Reduction:
- Finally, we reduce 'b' to S using the rule S → b, producing "S".
Output Sequence
Now, we track the printed outputs during parsing:
- For the first 'b' (S → bS): print "y".
- For the second 'b' (S → bS): print "y".
- For the third 'b' (S → bS): print "y".
- For the 'a' (S → aS): print "x".
- For the last 'a' (S → a): print "z".
Combining these outputs in the order they were printed:
- From 'b' (first): y
- From 'b' (second): y
- From 'b' (third): y
- From 'a': x
- From the last 'a': z
The final output is: zyyyxy.
Conclusion
Thus, the final output string for the input "babbba" is zyyyxy, which corresponds to option 'C'.
In the given SDT for the grammar, we have rules for the productions of S that also include printing certain characters based on the production rules used.
Production Rules
- S → aS { print "x"}
- S → bS { print "y"}
- S → a { print "z"}
- S → b { print "z"}
Input String: babbba
We will process the input "babbba" using a bottom-up parsing approach:
1. Parsing Steps:
- The input starts with 'b'. According to the rules, S can derive bS, so we apply that rule.
- After the first 'b', we have "abbba".
- Again, we can apply the rule S → bS for the second 'b', resulting in "abbb".
- Continue this process:
- S → bS for the third 'b', leading to "ab".
- S → aS for the 'a', resulting in "b".
2. Final Reduction:
- Finally, we reduce 'b' to S using the rule S → b, producing "S".
Output Sequence
Now, we track the printed outputs during parsing:
- For the first 'b' (S → bS): print "y".
- For the second 'b' (S → bS): print "y".
- For the third 'b' (S → bS): print "y".
- For the 'a' (S → aS): print "x".
- For the last 'a' (S → a): print "z".
Combining these outputs in the order they were printed:
- From 'b' (first): y
- From 'b' (second): y
- From 'b' (third): y
- From 'a': x
- From the last 'a': z
The final output is: zyyyxy.
Conclusion
Thus, the final output string for the input "babbba" is zyyyxy, which corresponds to option 'C'.
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Consider the given SDT which will be executed in connection with a bottom-up parser. For the input babbba, what will be the final output?S →aS { print “x”}S →bS { print “y”}S →a { print “z”}S →b { print “z”}a)zxyyyxb)zyxxxyc)zyyyxyd)zxxxyxCorrect answer is option 'C'. Can you explain this answer?
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Consider the given SDT which will be executed in connection with a bottom-up parser. For the input babbba, what will be the final output?S →aS { print “x”}S →bS { print “y”}S →a { print “z”}S →b { print “z”}a)zxyyyxb)zyxxxyc)zyyyxyd)zxxxyxCorrect answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Consider the given SDT which will be executed in connection with a bottom-up parser. For the input babbba, what will be the final output?S →aS { print “x”}S →bS { print “y”}S →a { print “z”}S →b { print “z”}a)zxyyyxb)zyxxxyc)zyyyxyd)zxxxyxCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the given SDT which will be executed in connection with a bottom-up parser. For the input babbba, what will be the final output?S →aS { print “x”}S →bS { print “y”}S →a { print “z”}S →b { print “z”}a)zxyyyxb)zyxxxyc)zyyyxyd)zxxxyxCorrect answer is option 'C'. Can you explain this answer?.
Consider the given SDT which will be executed in connection with a bottom-up parser. For the input babbba, what will be the final output?S →aS { print “x”}S →bS { print “y”}S →a { print “z”}S →b { print “z”}a)zxyyyxb)zyxxxyc)zyyyxyd)zxxxyxCorrect answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Consider the given SDT which will be executed in connection with a bottom-up parser. For the input babbba, what will be the final output?S →aS { print “x”}S →bS { print “y”}S →a { print “z”}S →b { print “z”}a)zxyyyxb)zyxxxyc)zyyyxyd)zxxxyxCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the given SDT which will be executed in connection with a bottom-up parser. For the input babbba, what will be the final output?S →aS { print “x”}S →bS { print “y”}S →a { print “z”}S →b { print “z”}a)zxyyyxb)zyxxxyc)zyyyxyd)zxxxyxCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Consider the given SDT which will be executed in connection with a bottom-up parser. For the input babbba, what will be the final output?S →aS { print “x”}S →bS { print “y”}S →a { print “z”}S →b { print “z”}a)zxyyyxb)zyxxxyc)zyyyxyd)zxxxyxCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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