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A balloon is at a height of 81 m and is ascending upwards with a velocity of 12 m/s. A body of 2 kg weight is dropped from it. If g=10m/s^2, the body will reach the surface of the earth in-?
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A balloon is at a height of 81 m and is ascending upwards with a veloc...
Answer:
Given:
- Height of balloon = 81 m
- Velocity of balloon = 12 m/s
- Weight of body = 2 kg
- Acceleration due to gravity = 10 m/s^2
To find:
- Time taken by body to reach surface of the earth
Explanation:
When the body is dropped from the balloon, it starts falling down under the influence of gravity. The velocity of the body increases due to the acceleration due to gravity. When the body reaches the surface of the earth, its velocity becomes maximum and is given by the formula:
v^2 = u^2 + 2as
where
v = final velocity = 0 m/s (as the body comes to rest on reaching the surface)
u = initial velocity = 0 m/s (as the body is dropped from rest)
a = acceleration due to gravity = 10 m/s^2
s = distance travelled by the body = height of balloon = 81 m
On substituting the values in the above formula, we get:
0^2 = 0^2 + 2(10)(81)
0 = 0 + 1620
t = sqrt(1620/10)
t = sqrt(162)
t = 12.73 seconds (approx)
Therefore, the body will reach the surface of the earth in approximately 12.73 seconds.
Conclusion:
The time taken by the body to reach the surface of the earth is approximately 12.73 seconds.
Given:
- Height of balloon = 81 m
- Velocity of balloon = 12 m/s
- Weight of body = 2 kg
- Acceleration due to gravity = 10 m/s^2
To find:
- Time taken by body to reach surface of the earth
Explanation:
When the body is dropped from the balloon, it starts falling down under the influence of gravity. The velocity of the body increases due to the acceleration due to gravity. When the body reaches the surface of the earth, its velocity becomes maximum and is given by the formula:
v^2 = u^2 + 2as
where
v = final velocity = 0 m/s (as the body comes to rest on reaching the surface)
u = initial velocity = 0 m/s (as the body is dropped from rest)
a = acceleration due to gravity = 10 m/s^2
s = distance travelled by the body = height of balloon = 81 m
On substituting the values in the above formula, we get:
0^2 = 0^2 + 2(10)(81)
0 = 0 + 1620
t = sqrt(1620/10)
t = sqrt(162)
t = 12.73 seconds (approx)
Therefore, the body will reach the surface of the earth in approximately 12.73 seconds.
Conclusion:
The time taken by the body to reach the surface of the earth is approximately 12.73 seconds.
Community Answer
A balloon is at a height of 81 m and is ascending upwards with a veloc...
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A balloon is at a height of 81 m and is ascending upwards with a velocity of 12 m/s. A body of 2 kg weight is dropped from it. If g=10m/s^2, the body will reach the surface of the earth in-? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A balloon is at a height of 81 m and is ascending upwards with a velocity of 12 m/s. A body of 2 kg weight is dropped from it. If g=10m/s^2, the body will reach the surface of the earth in-? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A balloon is at a height of 81 m and is ascending upwards with a velocity of 12 m/s. A body of 2 kg weight is dropped from it. If g=10m/s^2, the body will reach the surface of the earth in-?.
A balloon is at a height of 81 m and is ascending upwards with a velocity of 12 m/s. A body of 2 kg weight is dropped from it. If g=10m/s^2, the body will reach the surface of the earth in-? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A balloon is at a height of 81 m and is ascending upwards with a velocity of 12 m/s. A body of 2 kg weight is dropped from it. If g=10m/s^2, the body will reach the surface of the earth in-? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A balloon is at a height of 81 m and is ascending upwards with a velocity of 12 m/s. A body of 2 kg weight is dropped from it. If g=10m/s^2, the body will reach the surface of the earth in-?.
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