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From a balloon rising vertically upwards at 5m/s a stone thrown up 10m/s relative to the balloon. Its velocity with respect to ground after 2 sec Ans is 5m/s how?
Most Upvoted Answer
From a balloon rising vertically upwards at 5m/s a stone thrown up 10m...
Use the formula V=U-g×t

M=10+5=15(u)

V=15-10×2

V=5m/s...!!😊👍👍
Community Answer
From a balloon rising vertically upwards at 5m/s a stone thrown up 10m...
As the stone is thrown from rising balloon , so the stone will have the velocity of balloon + the velocity with which it was thrown. I.e. 10m/s +5 m/s =15m/s so its initial velocity(u) becomes 15m/s. now use the formula v=u - gt and after putting all values you will get v= -5 m/s but as the stone is seen relative to ground that's why velocity will be equal to +5 m/s.
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From a balloon rising vertically upwards at 5m/s a stone thrown up 10m/s relative to the balloon. Its velocity with respect to ground after 2 sec Ans is 5m/s how?
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