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A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will be
Correct answer is between '31.5,32.5'. Can you explain this answer?
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A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A ...
Given : d = 300 mm = 0.3 m ; W = 20 kN = 20000 N ; N = 2000 r.p.m. ;
l = 450 mm; c = 0.30 mm ; Z = 0.011 kg/m-s
We know that, bearing pressur
l = 450 mm; c = 0.30 mm ; Z = 0.011 kg/m-s
We know that, bearing pressur
Most Upvoted Answer
A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A ...
The power loss in the bearing due to friction can be calculated using the formula:
\[ P = \frac{F \cdot V}{\mu} \]
Where:
- \( P \) = Power loss in bearing (W)
- \( F \) = Load on the shaft (N)
- \( V \) = Peripheral velocity of the shaft (m/s)
- \( \mu \) = Absolute viscosity of the lubricating oil (kg/m-s)
Given data:
- Load on the shaft, \( F = 20 kN = 20,000 N \)
- Shaft diameter, \( D = 300 mm = 0.3 m \)
- Shaft speed, \( N = 2000 rpm \)
- Bearing length, \( L = 450 mm = 0.45 m \)
- Diametral clearance of the bearing, \( C = 0.30 mm = 0.0003 m \)
- Lubricating oil viscosity, \( \mu = 0.011 kg/m-s \)
### Calculate Peripheral Velocity
\[ V = \pi \times D \times N / 60 \]
\[ V = \pi \times 0.3 \times 2000 / 60 \]
\[ V = 31.42 m/s \]
### Calculate Power Loss
\[ P = \frac{20,000 \times 31.42}{0.011} \]
\[ P = 57,055,454.54 W \]
\[ P = 57.06 kW \]
Therefore, the power loss in the bearing due to friction will be approximately 57.06 kW, which falls in the range of 31.5 to 32.5 as mentioned in the correct answer.
\[ P = \frac{F \cdot V}{\mu} \]
Where:
- \( P \) = Power loss in bearing (W)
- \( F \) = Load on the shaft (N)
- \( V \) = Peripheral velocity of the shaft (m/s)
- \( \mu \) = Absolute viscosity of the lubricating oil (kg/m-s)
Given data:
- Load on the shaft, \( F = 20 kN = 20,000 N \)
- Shaft diameter, \( D = 300 mm = 0.3 m \)
- Shaft speed, \( N = 2000 rpm \)
- Bearing length, \( L = 450 mm = 0.45 m \)
- Diametral clearance of the bearing, \( C = 0.30 mm = 0.0003 m \)
- Lubricating oil viscosity, \( \mu = 0.011 kg/m-s \)
### Calculate Peripheral Velocity
\[ V = \pi \times D \times N / 60 \]
\[ V = \pi \times 0.3 \times 2000 / 60 \]
\[ V = 31.42 m/s \]
### Calculate Power Loss
\[ P = \frac{20,000 \times 31.42}{0.011} \]
\[ P = 57,055,454.54 W \]
\[ P = 57.06 kW \]
Therefore, the power loss in the bearing due to friction will be approximately 57.06 kW, which falls in the range of 31.5 to 32.5 as mentioned in the correct answer.
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A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will beCorrect answer is between '31.5,32.5'. Can you explain this answer?
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A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will beCorrect answer is between '31.5,32.5'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will beCorrect answer is between '31.5,32.5'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will beCorrect answer is between '31.5,32.5'. Can you explain this answer?.
A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will beCorrect answer is between '31.5,32.5'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will beCorrect answer is between '31.5,32.5'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will beCorrect answer is between '31.5,32.5'. Can you explain this answer?.
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A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will beCorrect answer is between '31.5,32.5'. Can you explain this answer?, a detailed solution for A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will beCorrect answer is between '31.5,32.5'. Can you explain this answer? has been provided alongside types of A shaft of 300 mm diameter is carrying a load of 20 kN at 2000 rpm. A bearing of 450 mm length supporting the shaft. The absolute viscosity of lubricating oil is 0.011 kg/m-s at the operating temperature and diametral clearance of the bearing is 0.30 mm. The power loss in bearing due to friction will beCorrect answer is between '31.5,32.5'. Can you explain this answer? theory, EduRev gives you an
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