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A single acting reciprocating pump has a piston of 15 cm diameter and 22.5 cm stroke. The pump is required to deliver 0.29 m3 of water per minute at 75 rpm. If the suction and delivery heads are 3 m and 10 m respectively, then the percentage of slip of pump is
    Correct answer is between '2.7,2.8'. Can you explain this answer?
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    A single acting reciprocating pump has a piston of 15 cm diameter and ...
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    A single acting reciprocating pump has a piston of 15 cm diameter and ...
    Given data:
    Piston diameter (D) = 15 cm
    Stroke (L) = 22.5 cm
    Speed (N) = 75 rpm
    Discharge (Q) = 0.29 m3/min
    Suction head (Hs) = 3 m
    Delivery head (Hd) = 10 m

    We need to calculate the percentage of slip of the pump.

    Formulae used:
    1. Displacement (D) = πD²L/4
    2. Piston speed (V) = 2LN/60
    3. Theoretical discharge (Qth) = ADN/60
    where A is the area of the piston, A = πD²/4
    4. Actual discharge (Qa) = Qth x (1 - Slip/100)

    Calculation:
    1. Area of the piston (A) = πD²/4 = π(15)²/4 = 176.71 cm²
    2. Displacement (D) = πD²L/4 = π(15)²(22.5)/4 = 11909.5 cm³ = 0.0119 m³
    3. Piston speed (V) = 2LN/60 = 2(3.14)(15)(75)/60 = 235.62 cm/min = 3.93 cm/s
    4. Theoretical discharge (Qth) = ADN/60 = (176.71)(75)/60 = 220.89 cm³/s = 0.22089 m³/min
    5. Actual discharge (Qa) = Qth x (1 - Slip/100) = 0.29 m³/min
    0.29 = 0.22089 x (1 - Slip/100)
    Slip = 2.7344%

    Therefore, the percentage of slip of the pump is 2.7344% or approximately 2.7% to 2.8%.
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    A single acting reciprocating pump has a piston of 15 cm diameter and 22.5 cm stroke. The pump is required to deliver 0.29 m3of water per minute at 75 rpm. If the suction and delivery heads are 3 m and 10 m respectively, then the percentage of slip of pump isCorrect answer is between '2.7,2.8'. Can you explain this answer?
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