The epicyclic gear arrangement with the compound planets 3-4 is shown in figure. The number of teeth on gears 2, 3, 4 and 5 are 60, 20, 30 and 20 respectively. The annular gear 2 is keyed to the propeller shaft X which rotates at 650 rad/s (CCW). The shaft Y is free to rotate with respect to gear 5 which is fixed and makes the same no. of revolution as the arm. If 100 kW power is supplied to gear 2 then the holding torque (in N-m) on gear 5 is (assume 100% efficiency throughout)Correct answer is between '38,39'. Can you explain this answer?

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The epicyclic gear arrangement with the compound planets 3-4 is shown in figure. The number of teeth on gears 2, 3, 4 and 5 are 60, 20, 30 and 20 respectively. The annular gear 2 is keyed to the propeller shaft X which rotates at 650 rad/s (CCW). The shaft Y is free to rotate with respect to gear 5 which is fixed and makes the same no. of revolution as the arm. If 100 kW power is supplied to gear 2 then the holding torque (in N-m) on gear 5 is (assume 100% efficiency throughout)

Correct answer is between '38,39'. Can you explain this answer?

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The epicyclic gear arrangement with the compound planets 3-4 is shown ...

Given, T₂ = 60, T₃ = 30, T₄ = 30, T₅ = 20,ω₂ = 650 rad/s,
ω₅ = 0 rad/s, P =100 kW
First of all we need to find the angular velocity of arm 1.
Using algebraic method,

ω₁ = 520 rad/s (CCW)
Since the shaft Y will make same no. of revolution as arms, so
Speed of shaft X = 520 rad/s (CCW)
Torque on driving shaft X or gear 2

Since 100 % efficiency throughout, so power available at gear 5 of shaft Y = 100 kW
Torque on driving shaft Y or gear 5

So, the holding torque on gear 5 = 192.3−153.84 = 38.46 N -m

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The epicyclic gear arrangement with the compound planets 3-4 is shown in figure. The number of teeth on gears 2, 3, 4 and 5 are 60, 20, 30 and 20 respectively. The annular gear 2 is keyed to the propeller shaft X which rotates at 650 rad/s (CCW). The shaft Y is free to rotate with respect to gear 5 which is fixed and makes the same no. of revolution as the arm. If 100 kW power is supplied to gear 2 then the holding torque (in N-m) on gear 5 is (assume 100% efficiency throughout)Correct answer is between '38,39'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about The epicyclic gear arrangement with the compound planets 3-4 is shown in figure. The number of teeth on gears 2, 3, 4 and 5 are 60, 20, 30 and 20 respectively. The annular gear 2 is keyed to the propeller shaft X which rotates at 650 rad/s (CCW). The shaft Y is free to rotate with respect to gear 5 which is fixed and makes the same no. of revolution as the arm. If 100 kW power is supplied to gear 2 then the holding torque (in N-m) on gear 5 is (assume 100% efficiency throughout)Correct answer is between '38,39'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The epicyclic gear arrangement with the compound planets 3-4 is shown in figure. The number of teeth on gears 2, 3, 4 and 5 are 60, 20, 30 and 20 respectively. The annular gear 2 is keyed to the propeller shaft X which rotates at 650 rad/s (CCW). The shaft Y is free to rotate with respect to gear 5 which is fixed and makes the same no. of revolution as the arm. If 100 kW power is supplied to gear 2 then the holding torque (in N-m) on gear 5 is (assume 100% efficiency throughout)Correct answer is between '38,39'. Can you explain this answer?.

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