ANSWER

Vant off factor(i) = Total number of ions present in the solution
Ba(OH)2​→Ba+2+2OH−
So, the total number of ions in the solution is 3.

Understanding the Van't Hoff Factor
The van't Hoff factor (i) is a crucial concept in physical chemistry used to describe the degree of dissociation of an electrolyte in solution. For a strong electrolyte like Ba(OH)2, the van't Hoff factor can be determined based on its dissociation in water.
Dissociation of Ba(OH)2
When barium hydroxide (Ba(OH)2) dissolves in water, it dissociates completely into its constituent ions:
- Ba(OH)2 → Ba²⁺ + 2 OH⁻
This reaction indicates that one formula unit of Ba(OH)2 yields three particles in solution: one barium ion and two hydroxide ions.
Calculating the Van't Hoff Factor
To calculate the van't Hoff factor (i), you sum the total number of particles produced in solution:
- Total particles = 1 (Ba²⁺) + 2 (OH⁻) = 3
Thus, the van't Hoff factor for Ba(OH)2 is:
- i = 3
Significance of the Van't Hoff Factor
The van't Hoff factor is essential for predicting colligative properties, such as:
- Boiling point elevation
- Freezing point depression
- Osmotic pressure
For Ba(OH)2, knowing that it completely dissociates into three ions helps in accurately calculating these properties in dilute solutions.
Conclusion
In summary, for a dilute aqueous solution of the strong electrolyte Ba(OH)2, the van't Hoff factor is 3, which reflects its complete dissociation into three ions, crucial for understanding its behavior in solution.