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The van’t Hoff factor (i) for a dilute aqueous solution of the strong electrolyte potassium sulphate is
  • a)
    0
  • b)
    2
  • c)
    4
  • d)
    3
Correct answer is option 'D'. Can you explain this answer?
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The van’t Hoff factor (i) for a dilute aqueous solution of the strong...
If α = 1 (strong electrolyte) then van’t Hoff factor is 3.
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The van’t Hoff factor (i) for a dilute aqueous solution of the strong...
Van’t Hoff Factor for Potassium Sulphate Solution
To determine the van’t Hoff factor (i) for a dilute aqueous solution of potassium sulphate, we need to understand the nature of the solute and its behavior in solution.

Key Points:
- Potassium sulphate (K2SO4) is a strong electrolyte that dissociates completely in water.
- When potassium sulphate dissolves in water, it breaks down into its constituent ions: K+ and SO4^2-.
- Since potassium sulphate yields three ions (two K+ ions and one SO4^2- ion) when it dissociates, the van’t Hoff factor for potassium sulphate is 3.
Therefore, the correct answer is option 'D' - 3. This indicates that for every formula unit of potassium sulphate dissolved in water, it produces three ions, contributing to its colligative properties and osmotic pressure in solution.
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The van’t Hoff factor (i) for a dilute aqueous solution of the strong electrolyte potassium sulphate isa)0b)2c)4d)3Correct answer is option 'D'. Can you explain this answer?
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