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A radioactive nuclide A decays to nuclide B which further decays to C. Their disintegration constant are λ1 and λ2 respectively. At t = 0 only nuclei A are present. Number of nuclei A at t = 0 is N0.a)rate of decay of A will first increase and then decreaseb)number of nuclei of B will first increase and then decreasec)if λ2> λ1, then activity of B will always be higher than activity of Ad)if λ1>> λ2, then number of nucleus of C will always be less than number of nucleus of B.Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A radioactive nuclide A decays to nuclide B which further decays to C. Their disintegration constant are λ1 and λ2 respectively. At t = 0 only nuclei A are present. Number of nuclei A at t = 0 is N0.a)rate of decay of A will first increase and then decreaseb)number of nuclei of B will first increase and then decreasec)if λ2> λ1, then activity of B will always be higher than activity of Ad)if λ1>> λ2, then number of nucleus of C will always be less than number of nucleus of B.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A radioactive nuclide A decays to nuclide B which further decays to C. Their disintegration constant are λ1 and λ2 respectively. At t = 0 only nuclei A are present. Number of nuclei A at t = 0 is N0.a)rate of decay of A will first increase and then decreaseb)number of nuclei of B will first increase and then decreasec)if λ2> λ1, then activity of B will always be higher than activity of Ad)if λ1>> λ2, then number of nucleus of C will always be less than number of nucleus of B.Correct answer is option 'B'. Can you explain this answer?.

Solutions for A radioactive nuclide A decays to nuclide B which further decays to C. Their disintegration constant are λ1 and λ2 respectively. At t = 0 only nuclei A are present. Number of nuclei A at t = 0 is N0.a)rate of decay of A will first increase and then decreaseb)number of nuclei of B will first increase and then decreasec)if λ2> λ1, then activity of B will always be higher than activity of Ad)if λ1>> λ2, then number of nucleus of C will always be less than number of nucleus of B.Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of A radioactive nuclide A decays to nuclide B which further decays to C. Their disintegration constant are λ1 and λ2 respectively. At t = 0 only nuclei A are present. Number of nuclei A at t = 0 is N0.a)rate of decay of A will first increase and then decreaseb)number of nuclei of B will first increase and then decreasec)if λ2> λ1, then activity of B will always be higher than activity of Ad)if λ1>> λ2, then number of nucleus of C will always be less than number of nucleus of B.Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A radioactive nuclide A decays to nuclide B which further decays to C. Their disintegration constant are λ1 and λ2 respectively. At t = 0 only nuclei A are present. Number of nuclei A at t = 0 is N0.a)rate of decay of A will first increase and then decreaseb)number of nuclei of B will first increase and then decreasec)if λ2> λ1, then activity of B will always be higher than activity of Ad)if λ1>> λ2, then number of nucleus of C will always be less than number of nucleus of B.Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A radioactive nuclide A decays to nuclide B which further decays to C. Their disintegration constant are λ1 and λ2 respectively. At t = 0 only nuclei A are present. Number of nuclei A at t = 0 is N0.a)rate of decay of A will first increase and then decreaseb)number of nuclei of B will first increase and then decreasec)if λ2> λ1, then activity of B will always be higher than activity of Ad)if λ1>> λ2, then number of nucleus of C will always be less than number of nucleus of B.Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A radioactive nuclide A decays to nuclide B which further decays to C. Their disintegration constant are λ1 and λ2 respectively. At t = 0 only nuclei A are present. Number of nuclei A at t = 0 is N0.a)rate of decay of A will first increase and then decreaseb)number of nuclei of B will first increase and then decreasec)if λ2> λ1, then activity of B will always be higher than activity of Ad)if λ1>> λ2, then number of nucleus of C will always be less than number of nucleus of B.Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A radioactive nuclide A decays to nuclide B which further decays to C. Their disintegration constant are λ1 and λ2 respectively. At t = 0 only nuclei A are present. Number of nuclei A at t = 0 is N0.a)rate of decay of A will first increase and then decreaseb)number of nuclei of B will first increase and then decreasec)if λ2> λ1, then activity of B will always be higher than activity of Ad)if λ1>> λ2, then number of nucleus of C will always be less than number of nucleus of B.Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.