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A solenoid 4 cm in diameter and 20 CM in length has 250 turns and carries a current of 15 ampere calculate the flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid?
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**Calculation of Magnetic Field Inside the Solenoid**
To calculate the flux through the surface of the disc, we first need to calculate the magnetic field inside the solenoid. The magnetic field inside a solenoid can be calculated using the formula:
B = μ₀ * n * I
Where:
B is the magnetic field
μ₀ is the permeability of free space (4π × 10^-7 T·m/A)
n is the number of turns per unit length
I is the current flowing through the solenoid
Given that the solenoid has a diameter of 4 cm and a length of 20 cm, we can calculate the number of turns per unit length (n) using the formula:
n = N / L
Where:
N is the total number of turns
L is the length of the solenoid
Substituting the given values, we get:
n = 250 / 0.2 = 1250 turns/m
Now we can calculate the magnetic field inside the solenoid:
B = (4π × 10^-7 T·m/A) * (1250 turns/m) * (15 A) = 7.5π × 10^-4 T
**Calculation of Flux through the Disc**
To calculate the flux through the surface of the disc, we can use the formula:
Φ = B * A
Where:
Φ is the magnetic flux
B is the magnetic field
A is the area of the disc
Given that the radius of the disc is 10 cm, the area of the disc can be calculated using the formula:
A = π * r²
Substituting the given value, we get:
A = π * (0.1 m)² = 0.01π m²
Now we can calculate the flux through the disc:
Φ = (7.5π × 10^-4 T) * (0.01π m²) = 7.5 × 10^-6 Wb
Therefore, the flux through the surface of the disc is 7.5 × 10^-6 Weber.
To calculate the flux through the surface of the disc, we first need to calculate the magnetic field inside the solenoid. The magnetic field inside a solenoid can be calculated using the formula:
B = μ₀ * n * I
Where:
B is the magnetic field
μ₀ is the permeability of free space (4π × 10^-7 T·m/A)
n is the number of turns per unit length
I is the current flowing through the solenoid
Given that the solenoid has a diameter of 4 cm and a length of 20 cm, we can calculate the number of turns per unit length (n) using the formula:
n = N / L
Where:
N is the total number of turns
L is the length of the solenoid
Substituting the given values, we get:
n = 250 / 0.2 = 1250 turns/m
Now we can calculate the magnetic field inside the solenoid:
B = (4π × 10^-7 T·m/A) * (1250 turns/m) * (15 A) = 7.5π × 10^-4 T
**Calculation of Flux through the Disc**
To calculate the flux through the surface of the disc, we can use the formula:
Φ = B * A
Where:
Φ is the magnetic flux
B is the magnetic field
A is the area of the disc
Given that the radius of the disc is 10 cm, the area of the disc can be calculated using the formula:
A = π * r²
Substituting the given value, we get:
A = π * (0.1 m)² = 0.01π m²
Now we can calculate the flux through the disc:
Φ = (7.5π × 10^-4 T) * (0.01π m²) = 7.5 × 10^-6 Wb
Therefore, the flux through the surface of the disc is 7.5 × 10^-6 Weber.
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A solenoid 4 cm in diameter and 20 CM in length has 250 turns and carries a current of 15 ampere calculate the flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid?
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A solenoid 4 cm in diameter and 20 CM in length has 250 turns and carries a current of 15 ampere calculate the flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solenoid 4 cm in diameter and 20 CM in length has 250 turns and carries a current of 15 ampere calculate the flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solenoid 4 cm in diameter and 20 CM in length has 250 turns and carries a current of 15 ampere calculate the flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid?.
A solenoid 4 cm in diameter and 20 CM in length has 250 turns and carries a current of 15 ampere calculate the flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solenoid 4 cm in diameter and 20 CM in length has 250 turns and carries a current of 15 ampere calculate the flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solenoid 4 cm in diameter and 20 CM in length has 250 turns and carries a current of 15 ampere calculate the flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid?.
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