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A solenoid 4cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. calculate flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid.?
Most Upvoted Answer
A solenoid 4cm in diameter and 20 cm in length has 250 turns and carri...
Itss too easy put the formula of flux theta=0• because magnetic field is normal to the area (gkp=1..page no. 93)
¤ = BAcos0•
B=u.nI.
A=πr2(area of circle)
(u.nI)×πr2=29.6×10-6 wb
¤ = BAcos0•
B=u.nI.
A=πr2(area of circle)
(u.nI)×πr2=29.6×10-6 wb
Community Answer
A solenoid 4cm in diameter and 20 cm in length has 250 turns and carri...
Solenoid Parameters:
- Diameter: 4 cm
- Length: 20 cm
- Number of turns: 250
- Current: 15 A
Flux through a Disc:
To calculate the flux through a disc that is positioned perpendicular to and centered on the axis of the solenoid, we can use the formula for the magnetic field inside a solenoid and then integrate it over the area of the disc.
The magnetic field inside a solenoid is given by the formula:
B = μ₀ * n * I
Where:
- B is the magnetic field
- μ₀ is the permeability of free space (4π × 10^⁻7 T m/A)
- n is the number of turns per unit length (n = N/L, where N is the total number of turns and L is the length of the solenoid)
- I is the current
Calculating Magnetic Field:
First, let's calculate the number of turns per unit length:
n = N/L = 250 turns / 0.2 m = 1250 turns/m
Now, we can calculate the magnetic field at the center of the solenoid:
B = (4π × 10^⁻7 T m/A) * (1250 turns/m) * (15 A) = 7.5 × 10^⁻3 T
Calculating Flux:
To calculate the flux through the surface of the disc, we need to consider the magnetic field passing through each small area element dA and integrate it over the entire area of the disc.
Let's assume the radius of the disc is r = 10 cm = 0.1 m. The area of the disc is given by the formula A = π * r^2.
Now, we can calculate the flux through the disc using the formula:
Φ = ∫B * dA
Since the magnetic field is uniform inside the solenoid, we can take it out of the integral:
Φ = B * ∫dA
Integrating over the area of the disc:
Φ = B * π * r^2
Plugging in the values:
Φ = (7.5 × 10^⁻3 T) * π * (0.1 m)^2 = 2.36 × 10^⁻4 T m²
Final Answer:
Therefore, the flux through the surface of the disc is 2.36 × 10^⁻4 T m².
- Diameter: 4 cm
- Length: 20 cm
- Number of turns: 250
- Current: 15 A
Flux through a Disc:
To calculate the flux through a disc that is positioned perpendicular to and centered on the axis of the solenoid, we can use the formula for the magnetic field inside a solenoid and then integrate it over the area of the disc.
The magnetic field inside a solenoid is given by the formula:
B = μ₀ * n * I
Where:
- B is the magnetic field
- μ₀ is the permeability of free space (4π × 10^⁻7 T m/A)
- n is the number of turns per unit length (n = N/L, where N is the total number of turns and L is the length of the solenoid)
- I is the current
Calculating Magnetic Field:
First, let's calculate the number of turns per unit length:
n = N/L = 250 turns / 0.2 m = 1250 turns/m
Now, we can calculate the magnetic field at the center of the solenoid:
B = (4π × 10^⁻7 T m/A) * (1250 turns/m) * (15 A) = 7.5 × 10^⁻3 T
Calculating Flux:
To calculate the flux through the surface of the disc, we need to consider the magnetic field passing through each small area element dA and integrate it over the entire area of the disc.
Let's assume the radius of the disc is r = 10 cm = 0.1 m. The area of the disc is given by the formula A = π * r^2.
Now, we can calculate the flux through the disc using the formula:
Φ = ∫B * dA
Since the magnetic field is uniform inside the solenoid, we can take it out of the integral:
Φ = B * ∫dA
Integrating over the area of the disc:
Φ = B * π * r^2
Plugging in the values:
Φ = (7.5 × 10^⁻3 T) * π * (0.1 m)^2 = 2.36 × 10^⁻4 T m²
Final Answer:
Therefore, the flux through the surface of the disc is 2.36 × 10^⁻4 T m².
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A solenoid 4cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. calculate flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid.?
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A solenoid 4cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. calculate flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solenoid 4cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. calculate flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solenoid 4cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. calculate flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid.?.
A solenoid 4cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. calculate flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A solenoid 4cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. calculate flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solenoid 4cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. calculate flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid.?.
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