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In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave
55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage
composition of nitrogen in the compound would be (Aqueous tension at 300 K = 15 mm)
55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage
composition of nitrogen in the compound would be (Aqueous tension at 300 K = 15 mm)
- a)14.45
- b)15.45
- c)16.45
- d)17.45
Correct answer is option 'C'. Can you explain this answer?
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In Dumas' method of estimation of nitrogen 0.35 g of an organic co...
Given:
Mass of organic compound = 0.35 g
Volume of nitrogen collected = 55 mL
Temperature = 300 K
Pressure = 715 mm
Aqueous tension at 300 K = 15 mm
To Find:
Percentage composition of nitrogen in the compound
Solution:
To find the percentage composition of nitrogen in the compound, we need to determine the moles of nitrogen and the moles of the organic compound.
Step 1: Calculate the moles of nitrogen
Using the ideal gas law equation:
PV = nRT
Where,
P = pressure (in atm)
V = volume (in L)
n = moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (in K)
Converting the given pressure and volume to atm and L respectively:
Pressure = 715 mm = 0.715 atm
Volume = 55 mL = 0.055 L
Substituting the values into the ideal gas law equation:
0.715 atm * 0.055 L = n * 0.0821 L.atm/mol.K * 300 K
Solving for n (moles of nitrogen):
n = (0.715 atm * 0.055 L) / (0.0821 L.atm/mol.K * 300 K)
n = 0.00137 mol
Step 2: Calculate the moles of the organic compound
The molar mass of nitrogen is 14 g/mol. Since the compound contains nitrogen, the moles of the compound will be equal to the moles of nitrogen.
Moles of organic compound = 0.00137 mol
Step 3: Calculate the percentage composition of nitrogen
The percentage composition of nitrogen can be calculated using the formula:
% composition = (moles of nitrogen / moles of organic compound) * 100
Substituting the values:
% composition = (0.00137 mol / 0.35 g) * 100
% composition = 0.3914%
Step 4: Correct for aqueous tension
The aqueous tension at 300 K is given as 15 mm. This needs to be subtracted from the atmospheric pressure to obtain the corrected pressure.
Corrected pressure = 715 mm - 15 mm = 700 mm
Step 5: Recalculate the moles of nitrogen
Using the corrected pressure of 700 mm:
Pressure = 700 mm = 0.700 atm
Substituting the values into the ideal gas law equation:
0.700 atm * 0.055 L = n * 0.0821 L.atm/mol.K * 300 K
Solving for n (moles of nitrogen):
n = (0.700 atm * 0.055 L) / (0.0821 L.atm/mol.K * 300 K)
n = 0.00142 mol
Step 6: Recalculate the percentage composition of nitrogen
% composition = (moles of nitrogen / moles of organic compound) * 100
Substituting the values:
% composition = (0.00142 mol / 0.35 g) * 100
% composition = 0.4057%
Mass of organic compound = 0.35 g
Volume of nitrogen collected = 55 mL
Temperature = 300 K
Pressure = 715 mm
Aqueous tension at 300 K = 15 mm
To Find:
Percentage composition of nitrogen in the compound
Solution:
To find the percentage composition of nitrogen in the compound, we need to determine the moles of nitrogen and the moles of the organic compound.
Step 1: Calculate the moles of nitrogen
Using the ideal gas law equation:
PV = nRT
Where,
P = pressure (in atm)
V = volume (in L)
n = moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (in K)
Converting the given pressure and volume to atm and L respectively:
Pressure = 715 mm = 0.715 atm
Volume = 55 mL = 0.055 L
Substituting the values into the ideal gas law equation:
0.715 atm * 0.055 L = n * 0.0821 L.atm/mol.K * 300 K
Solving for n (moles of nitrogen):
n = (0.715 atm * 0.055 L) / (0.0821 L.atm/mol.K * 300 K)
n = 0.00137 mol
Step 2: Calculate the moles of the organic compound
The molar mass of nitrogen is 14 g/mol. Since the compound contains nitrogen, the moles of the compound will be equal to the moles of nitrogen.
Moles of organic compound = 0.00137 mol
Step 3: Calculate the percentage composition of nitrogen
The percentage composition of nitrogen can be calculated using the formula:
% composition = (moles of nitrogen / moles of organic compound) * 100
Substituting the values:
% composition = (0.00137 mol / 0.35 g) * 100
% composition = 0.3914%
Step 4: Correct for aqueous tension
The aqueous tension at 300 K is given as 15 mm. This needs to be subtracted from the atmospheric pressure to obtain the corrected pressure.
Corrected pressure = 715 mm - 15 mm = 700 mm
Step 5: Recalculate the moles of nitrogen
Using the corrected pressure of 700 mm:
Pressure = 700 mm = 0.700 atm
Substituting the values into the ideal gas law equation:
0.700 atm * 0.055 L = n * 0.0821 L.atm/mol.K * 300 K
Solving for n (moles of nitrogen):
n = (0.700 atm * 0.055 L) / (0.0821 L.atm/mol.K * 300 K)
n = 0.00142 mol
Step 6: Recalculate the percentage composition of nitrogen
% composition = (moles of nitrogen / moles of organic compound) * 100
Substituting the values:
% composition = (0.00142 mol / 0.35 g) * 100
% composition = 0.4057%
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In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentagecomposition of nitrogen in the compound would be (Aqueous tension at 300 K = 15 mm)a)14.45b)15.45c)16.45d)17.45Correct answer is option 'C'. Can you explain this answer?
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In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentagecomposition of nitrogen in the compound would be (Aqueous tension at 300 K = 15 mm)a)14.45b)15.45c)16.45d)17.45Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentagecomposition of nitrogen in the compound would be (Aqueous tension at 300 K = 15 mm)a)14.45b)15.45c)16.45d)17.45Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentagecomposition of nitrogen in the compound would be (Aqueous tension at 300 K = 15 mm)a)14.45b)15.45c)16.45d)17.45Correct answer is option 'C'. Can you explain this answer?.
In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentagecomposition of nitrogen in the compound would be (Aqueous tension at 300 K = 15 mm)a)14.45b)15.45c)16.45d)17.45Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentagecomposition of nitrogen in the compound would be (Aqueous tension at 300 K = 15 mm)a)14.45b)15.45c)16.45d)17.45Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentagecomposition of nitrogen in the compound would be (Aqueous tension at 300 K = 15 mm)a)14.45b)15.45c)16.45d)17.45Correct answer is option 'C'. Can you explain this answer?.
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