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In Dumas method for estimation of nitrogen 0.30 g of an organic compound gave 50 ml of nitrogen collected at 300 K and 715 mm of Hg pressure. The percentage composition of nitrogen in the compound is, if aqueous tension at 300 K is 15 mm of Hg.
- a)37%
- b)17%
- c)57%
- d)75%
Correct answer is option 'B'. Can you explain this answer?
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In Dumas method for estimation of nitrogen 0.30 g of an organic compo...
W = 0.30 g
V1 = 50 ml
P1 = (P – a) = 715 – 15 = 700 mm of Hg
T1 = 300 K
Where a = aqueous tension
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In Dumas method for estimation of nitrogen 0.30 g of an organic compo...
Dumas Method for Estimation of Nitrogen
The Dumas method is a common technique used to estimate the percentage composition of nitrogen in an organic compound. It involves the combustion of the organic compound and the collection of the produced nitrogen gas.
Given Data:
- Mass of organic compound = 0.30 g
- Volume of nitrogen gas collected = 50 ml
- Temperature = 300 K
- Pressure = 715 mm Hg
- Aqueous tension at 300 K = 15 mm Hg
Calculations:
Step 1: Convert pressure to atm
To perform calculations, it is necessary to convert the pressure from mm Hg to atm. The conversion factor is 1 atm = 760 mm Hg.
Pressure (atm) = 715 mm Hg / 760 mm Hg/atm
Pressure (atm) = 0.9408 atm
Step 2: Corrected pressure
The corrected pressure is calculated by subtracting the aqueous tension from the measured pressure.
Corrected pressure (atm) = Pressure (atm) - Aqueous tension (atm)
Corrected pressure (atm) = 0.9408 atm - 0.0197 atm
Corrected pressure (atm) = 0.9211 atm
Step 3: Convert volume to moles
The collected volume of nitrogen gas needs to be converted to moles using the ideal gas law equation: PV = nRT.
n = PV / RT
n = (0.9211 atm) * (0.050 L) / (0.0821 L.atm/mol.K) * (300 K)
n = 0.001958 mol
Step 4: Calculate percentage composition of nitrogen
The molar mass of nitrogen (N₂) is 28 g/mol. Therefore, the mass of nitrogen in the compound can be calculated as follows:
Mass of nitrogen = n * Molar mass of nitrogen
Mass of nitrogen = 0.001958 mol * 28 g/mol
Mass of nitrogen = 0.05477 g
Percentage composition of nitrogen = (Mass of nitrogen / Mass of organic compound) * 100
Percentage composition of nitrogen = (0.05477 g / 0.30 g) * 100
Percentage composition of nitrogen = 18.26%
Answer:
The percentage composition of nitrogen in the compound is approximately 18.26%. Therefore, the correct option is option 'B' (17%).
The Dumas method is a common technique used to estimate the percentage composition of nitrogen in an organic compound. It involves the combustion of the organic compound and the collection of the produced nitrogen gas.
Given Data:
- Mass of organic compound = 0.30 g
- Volume of nitrogen gas collected = 50 ml
- Temperature = 300 K
- Pressure = 715 mm Hg
- Aqueous tension at 300 K = 15 mm Hg
Calculations:
Step 1: Convert pressure to atm
To perform calculations, it is necessary to convert the pressure from mm Hg to atm. The conversion factor is 1 atm = 760 mm Hg.
Pressure (atm) = 715 mm Hg / 760 mm Hg/atm
Pressure (atm) = 0.9408 atm
Step 2: Corrected pressure
The corrected pressure is calculated by subtracting the aqueous tension from the measured pressure.
Corrected pressure (atm) = Pressure (atm) - Aqueous tension (atm)
Corrected pressure (atm) = 0.9408 atm - 0.0197 atm
Corrected pressure (atm) = 0.9211 atm
Step 3: Convert volume to moles
The collected volume of nitrogen gas needs to be converted to moles using the ideal gas law equation: PV = nRT.
n = PV / RT
n = (0.9211 atm) * (0.050 L) / (0.0821 L.atm/mol.K) * (300 K)
n = 0.001958 mol
Step 4: Calculate percentage composition of nitrogen
The molar mass of nitrogen (N₂) is 28 g/mol. Therefore, the mass of nitrogen in the compound can be calculated as follows:
Mass of nitrogen = n * Molar mass of nitrogen
Mass of nitrogen = 0.001958 mol * 28 g/mol
Mass of nitrogen = 0.05477 g
Percentage composition of nitrogen = (Mass of nitrogen / Mass of organic compound) * 100
Percentage composition of nitrogen = (0.05477 g / 0.30 g) * 100
Percentage composition of nitrogen = 18.26%
Answer:
The percentage composition of nitrogen in the compound is approximately 18.26%. Therefore, the correct option is option 'B' (17%).
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In Dumas method for estimation of nitrogen 0.30 g of an organic compound gave 50 ml of nitrogen collected at 300 K and 715 mm of Hg pressure. The percentage composition of nitrogen in the compound is, if aqueous tension at 300 K is 15 mm of Hg.a)37%b)17%c)57%d)75%Correct answer is option 'B'. Can you explain this answer?
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In Dumas method for estimation of nitrogen 0.30 g of an organic compound gave 50 ml of nitrogen collected at 300 K and 715 mm of Hg pressure. The percentage composition of nitrogen in the compound is, if aqueous tension at 300 K is 15 mm of Hg.a)37%b)17%c)57%d)75%Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In Dumas method for estimation of nitrogen 0.30 g of an organic compound gave 50 ml of nitrogen collected at 300 K and 715 mm of Hg pressure. The percentage composition of nitrogen in the compound is, if aqueous tension at 300 K is 15 mm of Hg.a)37%b)17%c)57%d)75%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Dumas method for estimation of nitrogen 0.30 g of an organic compound gave 50 ml of nitrogen collected at 300 K and 715 mm of Hg pressure. The percentage composition of nitrogen in the compound is, if aqueous tension at 300 K is 15 mm of Hg.a)37%b)17%c)57%d)75%Correct answer is option 'B'. Can you explain this answer?.
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