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The power delivered to a single phase inductive load is measured with a dynamometer type wattmeter using a potential transformer (PT) of turns ratio 200:1 and the current transformer (CT) of turns ratio 1:5. Assume both the transformers to be ideal. The power factor of the load is 0.8. If the wattmeter reading is 200W, then the apparent power of the load in kVA is _________.
    Correct answer is between '250,250'. Can you explain this answer?
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    To find the apparent power of the load, we need to calculate the product of the voltage and current. Given that the power factor is 0.8, we can use the following formula:

    Apparent Power (S) = Real Power (P) / Power Factor (PF)

    Given:
    Wattmeter reading (P) = 200 W
    Turns ratio of the potential transformer (PT) = 200:1
    Turns ratio of the current transformer (CT) = 1:5
    Power factor (PF) = 0.8

    Step 1: Calculate the primary voltage (Vp) using the potential transformer (PT).
    Vp = Voltage measured by the PT / Turns ratio of PT
    = Wattmeter reading (P) x Turns ratio of PT
    = 200 W x 200
    = 40000 V

    Step 2: Calculate the primary current (Ip) using the current transformer (CT).
    Ip = Current measured by the CT / Turns ratio of CT
    = Wattmeter reading (P) x Turns ratio of CT
    = 200 W x 1/5
    = 40 A

    Step 3: Calculate the apparent power (S) using the formula mentioned earlier.
    S = P / PF
    = 200 W / 0.8
    = 250 VA

    Since the question asks for the apparent power in kVA, we convert the value to kVA by dividing by 1000.
    Apparent Power (in kVA) = 250 VA / 1000
    = 0.25 kVA

    Therefore, the apparent power of the load is 0.25 kVA.
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    The power delivered to a single phase inductive load is measured with a dynamometer type wattmeter using a potential transformer (PT) of turns ratio 200:1 and the current transformer (CT) of turns ratio 1:5. Assume both the transformers to be ideal. The power factor of the load is 0.8. If the wattmeter reading is 200W, then the apparent power of the load in kVA is _________.Correct answer is between '250,250'. Can you explain this answer?
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    The power delivered to a single phase inductive load is measured with a dynamometer type wattmeter using a potential transformer (PT) of turns ratio 200:1 and the current transformer (CT) of turns ratio 1:5. Assume both the transformers to be ideal. The power factor of the load is 0.8. If the wattmeter reading is 200W, then the apparent power of the load in kVA is _________.Correct answer is between '250,250'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about The power delivered to a single phase inductive load is measured with a dynamometer type wattmeter using a potential transformer (PT) of turns ratio 200:1 and the current transformer (CT) of turns ratio 1:5. Assume both the transformers to be ideal. The power factor of the load is 0.8. If the wattmeter reading is 200W, then the apparent power of the load in kVA is _________.Correct answer is between '250,250'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The power delivered to a single phase inductive load is measured with a dynamometer type wattmeter using a potential transformer (PT) of turns ratio 200:1 and the current transformer (CT) of turns ratio 1:5. Assume both the transformers to be ideal. The power factor of the load is 0.8. If the wattmeter reading is 200W, then the apparent power of the load in kVA is _________.Correct answer is between '250,250'. Can you explain this answer?.
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