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A step-up chopper is used to feed a load at 400 V dc from a 250 V dc source. The inductor current is continuous. If the ‘off’ time of the switch is 20μs, the switching frequency of the chopper is kHz is __________.
Correct answer is '31.25'. Can you explain this answer?
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A step-up chopper is used to feed a load at 400 V dc from a 250 V dc s...
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A step-up chopper is used to feed a load at 400 V dc from a 250 V dc s...
Chopper has a duty cycle of 0.6, what is the value of the inductance required to maintain a ripple current of 2 A?
To solve this problem, we can use the following equation for the average output voltage of a step-up chopper:
Vout = (D/(1-D)) * Vin
where Vout is the average output voltage, Vin is the input voltage, and D is the duty cycle. We can rearrange this equation to solve for Vin:
Vin = Vout * (1-D)/D
Using the given values of Vout = 400 V, Vin = 250 V, and D = 0.6, we get:
Vin = 400 * (1-0.6)/0.6 = 266.67 V
Next, we can use the following equation for the average inductor current of a step-up chopper:
Iavg = (Vout - Vin)/L * T
where Iavg is the average inductor current, L is the inductance, and T is the period of the chopper. We can rearrange this equation to solve for L:
L = (Vout - Vin)/(Iavg * T)
The ripple current can be calculated as:
ΔI = Vout * D/(L * f)
where ΔI is the ripple current, f is the chopper frequency, and we assume a continuous inductor current. We can rearrange this equation to solve for L:
L = Vout * D/(ΔI * f)
Using the given values of Vout = 400 V, Vin = 266.67 V, D = 0.6, ΔI = 2 A, and assuming a chopper frequency of 10 kHz, we get:
L = 400 * 0.6/(2 * 10^4) = 0.012 H
Therefore, the inductance required to maintain a ripple current of 2 A is 0.012 H.
To solve this problem, we can use the following equation for the average output voltage of a step-up chopper:
Vout = (D/(1-D)) * Vin
where Vout is the average output voltage, Vin is the input voltage, and D is the duty cycle. We can rearrange this equation to solve for Vin:
Vin = Vout * (1-D)/D
Using the given values of Vout = 400 V, Vin = 250 V, and D = 0.6, we get:
Vin = 400 * (1-0.6)/0.6 = 266.67 V
Next, we can use the following equation for the average inductor current of a step-up chopper:
Iavg = (Vout - Vin)/L * T
where Iavg is the average inductor current, L is the inductance, and T is the period of the chopper. We can rearrange this equation to solve for L:
L = (Vout - Vin)/(Iavg * T)
The ripple current can be calculated as:
ΔI = Vout * D/(L * f)
where ΔI is the ripple current, f is the chopper frequency, and we assume a continuous inductor current. We can rearrange this equation to solve for L:
L = Vout * D/(ΔI * f)
Using the given values of Vout = 400 V, Vin = 266.67 V, D = 0.6, ΔI = 2 A, and assuming a chopper frequency of 10 kHz, we get:
L = 400 * 0.6/(2 * 10^4) = 0.012 H
Therefore, the inductance required to maintain a ripple current of 2 A is 0.012 H.
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A step-up chopper is used to feed a load at 400 V dc from a 250 V dc source. The inductor current is continuous. If the ‘off’ time of the switch is 20μs, the switching frequency of the chopper is kHz is __________.Correct answer is '31.25'. Can you explain this answer?
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A step-up chopper is used to feed a load at 400 V dc from a 250 V dc source. The inductor current is continuous. If the ‘off’ time of the switch is 20μs, the switching frequency of the chopper is kHz is __________.Correct answer is '31.25'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A step-up chopper is used to feed a load at 400 V dc from a 250 V dc source. The inductor current is continuous. If the ‘off’ time of the switch is 20μs, the switching frequency of the chopper is kHz is __________.Correct answer is '31.25'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A step-up chopper is used to feed a load at 400 V dc from a 250 V dc source. The inductor current is continuous. If the ‘off’ time of the switch is 20μs, the switching frequency of the chopper is kHz is __________.Correct answer is '31.25'. Can you explain this answer?.
A step-up chopper is used to feed a load at 400 V dc from a 250 V dc source. The inductor current is continuous. If the ‘off’ time of the switch is 20μs, the switching frequency of the chopper is kHz is __________.Correct answer is '31.25'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A step-up chopper is used to feed a load at 400 V dc from a 250 V dc source. The inductor current is continuous. If the ‘off’ time of the switch is 20μs, the switching frequency of the chopper is kHz is __________.Correct answer is '31.25'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A step-up chopper is used to feed a load at 400 V dc from a 250 V dc source. The inductor current is continuous. If the ‘off’ time of the switch is 20μs, the switching frequency of the chopper is kHz is __________.Correct answer is '31.25'. Can you explain this answer?.
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