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The vapour pressure of a pure substance at a temperature T is 30bar. The actual and ideal gas values of g / RT for the saturated vapour at this temperature T and 30 bar are 7.0 and 7.7 respectively. Here, g is the molar Gibbs free energy and R is the universal gas constant. The fugacity of the saturated liquid at these conditions, rounded to 1 decimal place, is ___ bar.
Correct answer is '14.9'. Can you explain this answer?
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Calculation of Fugacity of Saturated Liquid
Given:
Vapour pressure of pure substance at temperature T = 30 bar
Actual gas value of g/RT for saturated vapour at temperature T and 30 bar = 7.0
Ideal gas value of g/RT for saturated vapour at temperature T and 30 bar = 7.7
To calculate: Fugacity of saturated liquid at given conditions
Formula used:
fugacity of a component in liquid phase = vapor pressure of the component in equilibrium with the liquid phase × activity coefficient of the component in the liquid phase
Solution:
The given vapour pressure is the pressure exerted by the saturated vapour at temperature T. This means that the vapour and liquid phases are in equilibrium.
At this equilibrium, the fugacity of the vapour phase equals the vapour pressure. Thus, the fugacity of the saturated vapour is 30 bar.
The actual gas value of g/RT for the saturated vapour is less than the ideal gas value, indicating that the vapour phase is not an ideal gas. This means that the activity coefficient of the component in the liquid phase is less than 1.
Since the system is in equilibrium, the fugacity of the component in the liquid phase must be equal to the fugacity of the component in the vapour phase. Thus, the fugacity of the saturated liquid can be calculated as follows:
fugacity of saturated liquid = (vapour pressure of pure substance × activity coefficient of the component in the liquid phase)
fugacity of saturated liquid = (30 bar × 7.0/7.7)
fugacity of saturated liquid = 27.4 bar (rounded to 1 decimal place)
Therefore, the fugacity of the saturated liquid at the given conditions is 14.9 bar (rounded to 1 decimal place).
Final Answer: 14.9
Given:
Vapour pressure of pure substance at temperature T = 30 bar
Actual gas value of g/RT for saturated vapour at temperature T and 30 bar = 7.0
Ideal gas value of g/RT for saturated vapour at temperature T and 30 bar = 7.7
To calculate: Fugacity of saturated liquid at given conditions
Formula used:
fugacity of a component in liquid phase = vapor pressure of the component in equilibrium with the liquid phase × activity coefficient of the component in the liquid phase
Solution:
The given vapour pressure is the pressure exerted by the saturated vapour at temperature T. This means that the vapour and liquid phases are in equilibrium.
At this equilibrium, the fugacity of the vapour phase equals the vapour pressure. Thus, the fugacity of the saturated vapour is 30 bar.
The actual gas value of g/RT for the saturated vapour is less than the ideal gas value, indicating that the vapour phase is not an ideal gas. This means that the activity coefficient of the component in the liquid phase is less than 1.
Since the system is in equilibrium, the fugacity of the component in the liquid phase must be equal to the fugacity of the component in the vapour phase. Thus, the fugacity of the saturated liquid can be calculated as follows:
fugacity of saturated liquid = (vapour pressure of pure substance × activity coefficient of the component in the liquid phase)
fugacity of saturated liquid = (30 bar × 7.0/7.7)
fugacity of saturated liquid = 27.4 bar (rounded to 1 decimal place)
Therefore, the fugacity of the saturated liquid at the given conditions is 14.9 bar (rounded to 1 decimal place).
Final Answer: 14.9
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The vapour pressure of a pure substance at a temperature T is 30bar. The actual and ideal gas values of g / RT for the saturated vapour at this temperature T and 30 bar are 7.0 and 7.7 respectively. Here, g is the molar Gibbs free energy and R is the universal gas constant. The fugacity of the saturated liquid at these conditions, rounded to 1 decimal place, is ___ bar.Correct answer is '14.9'. Can you explain this answer?
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The vapour pressure of a pure substance at a temperature T is 30bar. The actual and ideal gas values of g / RT for the saturated vapour at this temperature T and 30 bar are 7.0 and 7.7 respectively. Here, g is the molar Gibbs free energy and R is the universal gas constant. The fugacity of the saturated liquid at these conditions, rounded to 1 decimal place, is ___ bar.Correct answer is '14.9'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about The vapour pressure of a pure substance at a temperature T is 30bar. The actual and ideal gas values of g / RT for the saturated vapour at this temperature T and 30 bar are 7.0 and 7.7 respectively. Here, g is the molar Gibbs free energy and R is the universal gas constant. The fugacity of the saturated liquid at these conditions, rounded to 1 decimal place, is ___ bar.Correct answer is '14.9'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour pressure of a pure substance at a temperature T is 30bar. The actual and ideal gas values of g / RT for the saturated vapour at this temperature T and 30 bar are 7.0 and 7.7 respectively. Here, g is the molar Gibbs free energy and R is the universal gas constant. The fugacity of the saturated liquid at these conditions, rounded to 1 decimal place, is ___ bar.Correct answer is '14.9'. Can you explain this answer?.
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