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In a group of cows and hens, the number of legs are 14 more than twice the number of heads. The number of cows is
  • a)
    5                          
  • b)
    7                       
  • c)
    10                         
  • d)
    12
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a group of cows and hens, the number of legs are 14 more than twice...
Let the number of cows be x and the number of hens be y. Then, 4x + 2y = 2 (x + y) + 14 4x + 2y = 2x + 2y + 14 2x = 14 x = 7.
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Community Answer
In a group of cows and hens, the number of legs are 14 more than twice...
To solve this problem, let's assume the number of cows as 'x' and the number of hens as 'y'.

Number of Legs:
Each cow has 4 legs, so the total number of cow legs is 4x.
Each hen has 2 legs, so the total number of hen legs is 2y.
The total number of legs can be calculated as 4x + 2y.

Number of Heads:
The number of cows is 'x', and the number of hens is 'y'. So the total number of heads can be calculated as x + y.

Given Information:
According to the problem, the number of legs is 14 more than twice the number of heads. Mathematically, this can be represented as:

4x + 2y = 2(x + y) + 14

Simplifying the equation, we get:

4x + 2y = 2x + 2y + 14

Subtracting 2x and 2y from both sides, we get:

2x = 14

Dividing both sides by 2, we get:

x = 7

Therefore, the number of cows is 7, which corresponds to option 'B'.
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In a group of cows and hens, the number of legs are 14 more than twice the number of heads. The number of cows isa)5 b)7 c)10 d)12Correct answer is option 'B'. Can you explain this answer?
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