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A single axis CNC table is driven by a DC servo motor that is directly coupled to a lead screw of 5 mm pitch. The circular encoder attached to the lead screw generates 1000 voltage pulses per revolution of the lead screw. The table moves at a constant speed of 6 m/min. The corresponding frequency (in kHz) of the voltage pulses generated by the circular encoder is________
Correct answer is '20'. Can you explain this answer?
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To find the frequency of the voltage pulses generated by the circular encoder, we need to calculate the number of pulses per second.
Given:
- Lead screw pitch = 5 mm
- Circular encoder generates 1000 voltage pulses per revolution of the lead screw
- Table moves at a constant speed of 6 m/min
Calculating the velocity:
- The table moves at a speed of 6 m/min, which can be converted to m/s by dividing it by 60: 6 m/min ÷ 60 = 0.1 m/s
Calculating the distance covered by the table in one second:
- The table moves at a velocity of 0.1 m/s, so in one second, it covers a distance of 0.1 meters.
Calculating the number of revolutions made by the lead screw in one second:
- Since the lead screw has a pitch of 5 mm, it covers a distance of 5 mm in one revolution.
- The distance covered by the table in one second is 0.1 meters, which is equal to 100 mm.
- Therefore, the number of revolutions made by the lead screw in one second is 100 mm ÷ 5 mm/rev = 20 revolutions.
Calculating the frequency of voltage pulses:
- The circular encoder generates 1000 voltage pulses per revolution of the lead screw.
- Since the lead screw makes 20 revolutions in one second, the circular encoder will generate 1000 pulses × 20 revolutions = 20,000 pulses in one second.
- The frequency of the voltage pulses is the number of pulses per second, so the frequency is 20,000 pulses/second = 20 kHz.
Therefore, the corresponding frequency of the voltage pulses generated by the circular encoder is 20 kHz.
Given:
- Lead screw pitch = 5 mm
- Circular encoder generates 1000 voltage pulses per revolution of the lead screw
- Table moves at a constant speed of 6 m/min
Calculating the velocity:
- The table moves at a speed of 6 m/min, which can be converted to m/s by dividing it by 60: 6 m/min ÷ 60 = 0.1 m/s
Calculating the distance covered by the table in one second:
- The table moves at a velocity of 0.1 m/s, so in one second, it covers a distance of 0.1 meters.
Calculating the number of revolutions made by the lead screw in one second:
- Since the lead screw has a pitch of 5 mm, it covers a distance of 5 mm in one revolution.
- The distance covered by the table in one second is 0.1 meters, which is equal to 100 mm.
- Therefore, the number of revolutions made by the lead screw in one second is 100 mm ÷ 5 mm/rev = 20 revolutions.
Calculating the frequency of voltage pulses:
- The circular encoder generates 1000 voltage pulses per revolution of the lead screw.
- Since the lead screw makes 20 revolutions in one second, the circular encoder will generate 1000 pulses × 20 revolutions = 20,000 pulses in one second.
- The frequency of the voltage pulses is the number of pulses per second, so the frequency is 20,000 pulses/second = 20 kHz.
Therefore, the corresponding frequency of the voltage pulses generated by the circular encoder is 20 kHz.
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A single axis CNC table is driven by a DC servo motor that is directly coupled to a lead screw of5 mm pitch. The circular encoder attached to the lead screw generates 1000 voltage pulses perrevolution of the lead screw. The table moves at a constant speed of 6 m/min. The correspondingfrequency (in kHz) of the voltage pulses generated by the circular encoder is________Correct answer is '20'. Can you explain this answer?
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