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A ray of light is incident at an angle of incidence 45º on an equilateral prism and emerge at an angle 45º then the refractive index of the medium of the prism is : 
  • a)
    2
  • b)
    (sqrt{2})
  • c)
    (1over sqrt{2})
  • d)
    ( sqrt{3} )
Correct answer is option 'B'. Can you explain this answer?
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Degrees on a glass slab. The angle of refraction is 30 degrees. Determine the refractive index of the glass slab.

The refractive index (n) can be calculated using Snell's law, which states that the ratio of the sine of the angle of incidence (i) to the sine of the angle of refraction (r) is equal to the ratio of the speed of light in the first medium (v1) to the speed of light in the second medium (v2).

Mathematically, Snell's law can be written as: n = (sin i) / (sin r)

In this case, the angle of incidence (i) is 45 degrees, and the angle of refraction (r) is 30 degrees. Substituting these values into Snell's law:

n = sin(45) / sin(30)

Using a scientific calculator to calculate the sines of the angles:

n ≈ 0.707 / 0.5

n ≈ 1.414

Therefore, the refractive index of the glass slab is approximately 1.414.
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A ray of light is incident at an angle of incidence 45º on an equilateral prism and emerge at an angle 45º then the refractive index of the medium of the prism is :a)2b)(sqrt{2})c)(1over sqrt{2})d)( sqrt{3} )Correct answer is option 'B'. Can you explain this answer?
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