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A direct bandgap semiconductor has a bandgap of 1.8 eV. The threshold value of the wavelength
BELOW which this material will absorb radiation is__________________ Å.
(Given: Planck’s constant, h = 6.626 × 10−34 J s, the charge of an electron, e = 1.6 × 10−19 C, and
speed of light, c = 3 × 108 m s−1)
    Correct answer is between '6850,6950'. Can you explain this answer?
    Most Upvoted Answer
    A direct bandgap semiconductor has a bandgap of 1.8 eV. The threshold ...
    To calculate the threshold value of the wavelength below which the material will absorb radiation, we can use the equation:

    Energy of a photon = Planck's constant * Speed of light / Wavelength

    Given that the bandgap of the direct bandgap semiconductor is 1.8 eV, we can convert this to joules by multiplying by the conversion factor 1.6 x 10^-19 J/eV:

    Energy of a photon = 1.8 eV * 1.6 x 10^-19 J/eV = 2.88 x 10^-19 J

    We can equate this energy to the equation above:

    2.88 x 10^-19 J = Planck's constant * Speed of light / Wavelength

    Rearranging the equation to solve for the wavelength:

    Wavelength = Planck's constant * Speed of light / 2.88 x 10^-19 J

    Using the values for Planck's constant (6.63 x 10^-34 J·s) and the speed of light (3 x 10^8 m/s):

    Wavelength = (6.63 x 10^-34 J·s * 3 x 10^8 m/s) / 2.88 x 10^-19 J

    Wavelength = 6.89 x 10^-7 m

    So, the threshold value of the wavelength below which the direct bandgap semiconductor will absorb radiation is approximately 6.89 x 10^-7 meters or 689 nm.
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    A direct bandgap semiconductor has a bandgap of 1.8 eV. The threshold value of the wavelengthBELOW which this material will absorb radiation is__________________ Å.(Given: Planck’s constant, h = 6.626 × 10−34 J s, the charge of an electron, e = 1.6 × 10−19 C, andspeed of light, c = 3 × 108 m s−1)Correct answer is between '6850,6950'. Can you explain this answer?
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    A direct bandgap semiconductor has a bandgap of 1.8 eV. The threshold value of the wavelengthBELOW which this material will absorb radiation is__________________ Å.(Given: Planck’s constant, h = 6.626 × 10−34 J s, the charge of an electron, e = 1.6 × 10−19 C, andspeed of light, c = 3 × 108 m s−1)Correct answer is between '6850,6950'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A direct bandgap semiconductor has a bandgap of 1.8 eV. The threshold value of the wavelengthBELOW which this material will absorb radiation is__________________ Å.(Given: Planck’s constant, h = 6.626 × 10−34 J s, the charge of an electron, e = 1.6 × 10−19 C, andspeed of light, c = 3 × 108 m s−1)Correct answer is between '6850,6950'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A direct bandgap semiconductor has a bandgap of 1.8 eV. The threshold value of the wavelengthBELOW which this material will absorb radiation is__________________ Å.(Given: Planck’s constant, h = 6.626 × 10−34 J s, the charge of an electron, e = 1.6 × 10−19 C, andspeed of light, c = 3 × 108 m s−1)Correct answer is between '6850,6950'. Can you explain this answer?.
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