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Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of80°C, the mass of water present will be :[Take specific heat of water = 1 cal g−1 °C−1 and latent heat of steam = 540 cal g−1]a)42.5 gb)22.5 gc)24 gd)31.5 gCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of80°C, the mass of water present will be :[Take specific heat of water = 1 cal g−1 °C−1 and latent heat of steam = 540 cal g−1]a)42.5 gb)22.5 gc)24 gd)31.5 gCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of80°C, the mass of water present will be :[Take specific heat of water = 1 cal g−1 °C−1 and latent heat of steam = 540 cal g−1]a)42.5 gb)22.5 gc)24 gd)31.5 gCorrect answer is option 'B'. Can you explain this answer?.

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Here you can find the meaning of Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of80°C, the mass of water present will be :[Take specific heat of water = 1 cal g−1 °C−1 and latent heat of steam = 540 cal g−1]a)42.5 gb)22.5 gc)24 gd)31.5 gCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of80°C, the mass of water present will be :[Take specific heat of water = 1 cal g−1 °C−1 and latent heat of steam = 540 cal g−1]a)42.5 gb)22.5 gc)24 gd)31.5 gCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of80°C, the mass of water present will be :[Take specific heat of water = 1 cal g−1 °C−1 and latent heat of steam = 540 cal g−1]a)42.5 gb)22.5 gc)24 gd)31.5 gCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of80°C, the mass of water present will be :[Take specific heat of water = 1 cal g−1 °C−1 and latent heat of steam = 540 cal g−1]a)42.5 gb)22.5 gc)24 gd)31.5 gCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of80°C, the mass of water present will be :[Take specific heat of water = 1 cal g−1 °C−1 and latent heat of steam = 540 cal g−1]a)42.5 gb)22.5 gc)24 gd)31.5 gCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.