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A man whose father was colour blind marries a woman, who had a colourblind mother and normal father. What percentage of male children of this couple will be colourblind.

  • a)
    25%

  • b)
    75%

  • c)
    50%

  • d)
    0%

Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A man whose father was colour blind marries a woman, who had a colourb...
Solution:
The given information can be represented in the form of a Punnett square as follows:

| | Xc | Xc |
|---|----|----|
| Xc| XcXc| XcXc|
| X | XcX | XX |

Where X represents the normal allele and Xc represents the colorblind allele.

From the Punnett square, we can see that:
- All the daughters will be carriers of the colorblind gene as they inherit one Xc allele from their mother and one X allele from their father.
- Half of the sons will be colorblind as they inherit one Xc allele from their mother and one X allele from their father.

Therefore, the percentage of male children who will be colorblind is 25% (half of the male children).

Hence, the correct answer is option C) 25%.
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Community Answer
A man whose father was colour blind marries a woman, who had a colourb...
Colour blind ness is due to the mutation of certain genes of x chromosome which is about 8 % in male and 0.4% in female. the son of a woman who carrier of it ,50% chance of colour blind .according to the question the father has 50% chance of being colour blind and he married a normal woman. the son of this couple having 25%chance of being colour blind because his x chromosome come from his mother and y chromosome come from his father, means half of chance of being colour blind so 25%is correct
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