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For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer?, a detailed solution for For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.