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For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer?.

Solutions for For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer?, a detailed solution for For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice For a saturated solution of AgCI at 25°C, k = 3.4 x 10-6ohm-1cm-1and that of H2O()used is 2.02 x 10-6ohm-1 cm-1. λ°mfor AgCI is 138 ohm-1cm2 mol-1, then the solubility of AgCl in moles per liter will be :a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.