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If am ≠ bl, then the system of equations, ax + by = c, lx + my = n
  • a)
    has a unique solution
  • b)
    has no solution
  • c)
    has infinitely many solutions
  • d)
    may or may not have a solution
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If am ≠ bl, then the system of equations, ax + by = c, lx + my = na...
If am ≠ bl, then the equations ax+by=c, lx+my=n has a unique solution.
Given,
Pair of lines represented by the equations
ax + by = c
lx + my = n
For unique solution
For infinite solutions
For no solution
Given,
This can be transformed into
Therefore, If am ≠ bl, then the equations ax+by=c, lx+my=n has a unique solution.
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Most Upvoted Answer
If am ≠ bl, then the system of equations, ax + by = c, lx + my = na...
It is given that am≠bl,
the given equations are:-
ax+by=c,
lx+my=n,
a1/a2=a/l,
b1/b2=b/m,
c1/c2=c/n,
since,a/l≠b/m,
or, as its given am≠bl,
a1/a2≠b1/b2 the pair of linear equation have a unique solution
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Community Answer
If am ≠ bl, then the system of equations, ax + by = c, lx + my = na...
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