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A mass m is constrained to move on a horizontal frictionless surface. It is set in circular m otion with radius r0 and angular speed w0 by an applied force com municated through an inextensible thread that passes through a hole on the surface as shown in the figure. This force is then suddenly doubled. The magnitude of the radial velocity of the mass
  • a)
    Increases till the mass falls into the hole.
  • b)
    Decreases till the mass falls into the hole.
  • c)
    remains constant.
  • d)
    Becomes zero at a radius r1 where 0 < r1 < r0
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A mass m is constrained to move on a horizontal frictionless surface. ...
The particle is moving in a circular motion with radius r0 and angular speed ω0 by an applied force F applied through an inextensible thread passing through hole.
The circular motion of the particle is, 
Now. when we doubled the force.

Subtract equation (A) from (B). we get



As the force increases, r will decrease and hence, velocity of particle will decrease till the fall into the hole.
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A mass m is constrained to move on a horizontal frictionless surface. It is set in circular m otion with radius r0 and angular speed w0 by an applied force com municated through an inextensible thread that passes through a hole on the surface as shown in the figure. This force is then suddenly doubled. The magnitude of the radial velocity of the massa)Increases till the mass falls into the hole.b)Decreases till the mass falls into the hole.c)remains constant.d)Becomes zero at a radius r1where 0 < r1< r0Correct answer is option 'B'. Can you explain this answer?
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