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A tuning fork of frequency 512 Hz is vibrated with a sonometer wire and 6 beats per second are heard. The beat frequency reduces if the tension in the string is slightly increased. The original frequency of vibration of the string is
  • a)
    506 Hz
  • b)
    512 Hz
  • c)
    518 Hz
  • d)
    524 Hz
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A tuning fork of frequency 512 Hz is vibrated with a sonometer wire an...
f1 = 512Hz
f2 = frequency of sonometer wire.
Now, 512 -f2 = 6
By increasing the tension in sonometer wire fwill increase.
In first case, beat frequency will decreae.
∴ 512 - f2 = 6
or f2 = 506 Hz
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Community Answer
A tuning fork of frequency 512 Hz is vibrated with a sonometer wire an...
Beats frequency, v = v1-v2 = 512-6= 506 Hz .Beats will be equal to frequency as nearly same frequencies and amplitude.
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A tuning fork of frequency 512 Hz is vibrated with a sonometer wire and 6 beats per second are heard. The beat frequency reduces if the tension in the string is slightly increased. The original frequency of vibration of the string isa)506 Hzb)512 Hzc)518 Hzd)524 HzCorrect answer is option 'A'. Can you explain this answer?
Question Description
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