Two charges + Q each are fixed at points C and D. Line AB is the bisector line of CD. A third charge +q is moved from A to B, then from B to Ca)From A to B electrostatic potential energy will decrease.b)From A to B electrostatic energy will increase.c)From B to C electrostatic potential energy will increase.d)From B to C electrostatic potential energy will decrease.Correct answer is option 'B,C'. Can you explain this answer?

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Two charges + Q each are fixed at points C and D. Line AB is the bisector line of CD. A third charge +q is moved from A to B, then from B to C

a)
From A to B electrostatic potential energy will decrease.
b)
From A to B electrostatic energy will increase.
c)
From B to C electrostatic potential energy will increase.
d)
From B to C electrostatic potential energy will decrease.

Correct answer is option 'B,C'. Can you explain this answer?

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Two charges + Q each are fixed at points C and D. Line AB is the bisec...

Along the line AB, charge q is at unstable equilibrium position at B (when displaced from B along AB, net force on it is away from B, where as force at B is zero) Hence potential energy at B is maximum.
Along CD equilibrium of q is stable. Hence potential energy at B is minimum along CD.

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Two charges + Q each are fixed at points C and D. Line AB is the bisector line of CD. A third charge +q is moved from A to B, then from B to Ca)From A to B electrostatic potential energy will decrease.b)From A to B electrostatic energy will increase.c)From B to C electrostatic potential energy will increase.d)From B to C electrostatic potential energy will decrease.Correct answer is option 'B,C'. Can you explain this answer?

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