A beam of plane-polarized light falls on a polarizer which rotates abo...
When the polarizer rotates with angular velocity ω its instantaneous principal direction makes angle ωt from a reference direction which we choose to be along the direction of vibration of the plane polarized incident light. The transmitted flux at this instant is
ωt and the total energy passing through the polarizer per revolution is
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A beam of plane-polarized light falls on a polarizer which rotates abo...
Let's call the angular velocity of the polarizer $\omega$. This means that the polarizer is rotating around its axis with an angular velocity of $\omega$.
When a beam of plane-polarized light falls on a polarizer, the polarizer only allows light waves with a specific polarization to pass through. In this case, let's assume that the polarizer is aligned with the polarization direction of the light beam initially.
As the polarizer starts to rotate with angular velocity $\omega$, the polarization direction of the polarizer changes over time. This means that the angle between the polarization direction of the light beam and the polarization direction of the polarizer also changes.
If the angle between the polarization direction of the light beam and the polarization direction of the polarizer is not 90 degrees, then some of the light will be transmitted through the polarizer. The amount of light transmitted depends on the angle between the polarization directions.
If the angle between the polarization directions is 90 degrees, then none of the light will be transmitted through the polarizer. This is because the polarizer only allows light waves with a specific polarization to pass through, and if the polarization direction of the light beam is perpendicular to the polarization direction of the polarizer, the light will not be able to pass through.
So, as the polarizer rotates with angular velocity $\omega$, the amount of light transmitted through the polarizer will change depending on the angle between the polarization directions.